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Pavlova-9 [17]
2 years ago
5

If 8.51÷2.3=3.7, find the value of 85.1÷ 2.3​

Mathematics
1 answer:
LiRa [457]2 years ago
8 0

Answer:

37

Step-by-step explanation:

85.1÷ 2.3​

=> 85.1/2.3 [Removing the decimals]

=> 851/23

=> 37

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What is normal, when it comes to people's body temperature? a random sample of 130 human body temperatures, provided by allen sh
nikitadnepr [17]
The two-sided alternative hypothesis is appropriate in this case, the reason being we are asked "does the data indicate that the average body temperature for healthy humans is different from 98.6◦........?".
The test statistic is:
Z= \frac{\bar{X}-\mu}{ \frac{s}{ \sqrt{n} } }} =-5.47
Using an inverse normal table, and halving \alpha for a two-tailed test, we look up p=0.5-\alpha/2=0.5-0.005=0.495 and find the critical value to be Z = 2.5758.
Comparing the test statistic Z = -5.47 with the rejection region Z < -2.5758 and Z > 2.5758. we find the test statistic lies in the rejection region. Therefore the evidence does not indicate that the average body temperature for healthy humans is different from 98.6◦.
 
7 0
3 years ago
Dan wants to drink 4 gallons of water of water over 5 days. if he finished 13 quarts of water after day 4, how many more quarts
Alexandra [31]
Dan needs to drink 3 more quarts of water
7 0
3 years ago
How do I do the square root of 8 squared?​
Yanka [14]
First, find out what 8^2 is.
(Answer = 64)

Then, find the square root of 64.
(Answer = 8)
8 0
3 years ago
Helppp I really need this question answered
Ne4ueva [31]

Answer:

32.5 units²

Step-by-step explanation:

We can find the area by dividing the figure into two shapes. If we solve for the area of a square and a triangle, we can add them together.

First, we can solve for the area of the 5x5 square. To find the area, we can multiply the two dimensions.

5 · 5 = 25 units²

Next, we can find the area of the triangle. It has an equal height to the square, so the height of the triangle is 5 units. The width isn't specified. Instead, we are shown that the width of both the square and the triangle equals 8 units. If we subtract the width of the square from the total, we can find the width of the triangle, too.

8 - 5 = 3

So, the height and the width of the triangle are 5x3. To find the area we can multiply these together, and then divide the product by two.

5 · 3 = 15

\frac{15}{2} = 7.5

The area of the triangle is 7.5 units².

Finally, we can add the area of the triangle and the square together.

25 + 7.5 = 32.5

The area of the figure, then, is 32.5 units².

The answer is the last option.

I hope this helps ^^

6 0
3 years ago
Let ​ f(x) = 4(x^2) - 3x
posledela

Answer:

(f+g)(x)=5x²-4x+3

(f-g)(x)=3x²-2x+3

(fg)(x)=4x^4-7x^3+15x^2-9x

\frac{f}{g}(x) =\frac{4x^2-3x}{x^2-x+3}

Step-by-step explanation:

Given that,

f(x)=4x²-3x

g(x)=x²-x+3

(f+g)(x)

=f(x)+g(x)

=4x²-3x+x²-x+3

=(4x²+x²)+(-3x-x)+3   [ combined the like terms]

=5x²-4x+3

(f-g)(x)

=f(x)-g(x)

=4x²-3x-(x²-x+3)

=4x²-3x-x²+x-3

=(4x²-x²)+(-3x+x)-3   [ combined the like terms]

=3x²-2x+3

(fg)(x)

=f(x).g(x)

=(4x²-3x).(x²-x+3)

=4x²(x²-x+3)-3x(x²-x+3)

=4x^4-4x^3+12x^2-3x^3+3x^2-9x

=4x^4+(-4x^3-3x^3)+(12x^2+3x^2)-9x

=4x^4-7x^3+15x^2-9x

\frac{f}{g}(x)

=\frac{f(x)}{g(x)}

=\frac{4x^2-3x}{x^2-x+3}

7 0
3 years ago
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