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2 years ago

If 8.51÷2.3=3.7, find the value of 85.1÷ 2.3

Mathematics

1 answer:

LiRa [457]2 years ago

8 0

Answer:

Step-by-step explanation:

85.1÷ 2.3

=> 85.1/2.3 [Removing the decimals]

=> 851/23

=> 37

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A philanthropic organization helped a town in Africa dig several wells to gain access to clean water. Before the wells were in p

Romashka [77]

Answer: -1.5

Step-by-step explanation:

When population standard deviation is known, then the formula to find the z-test statistic for population mean is given by :-

$z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

, where n= Sample size.

$\mu$ = Population mean

$\overline{x}$ = Sample mean

$\sigma$ = Population standard deviation.

As per given , we have $\mu=120$ (average infants contracted typhoid each month)

$\sigma=40$

n= 4 (No. of months)

$\overline{x}=90$

Then , the value of the appropriate test statistic will be :

$z=\dfrac{90-120}{\dfrac{40}{\sqrt{4}}}$

$z=\dfrac{-30}{\dfrac{40}{2}}$

$z=\dfrac{-30}{20}$

$z=-1.5$

Hence, the value of the test statistic = -1.5

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3 years ago

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Stels [109]

Answer:

2 half

Step-by-step explanation:

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2 years ago

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Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.