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AleksAgata [21]
3 years ago
11

HELP......... NO LINKS

Mathematics
1 answer:
MArishka [77]3 years ago
6 0

Answer:

y =54

Step-by-step explanation:

2(3)^3 - substitute x for 3, then find cube of 3( 3×3×3)

2×27

54

s

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What is the solution to the linear equation?
DIA [1.3K]

Answer:

the solution of linear equation 4b + 6 = 2 - 6 + 4 is b = -2

Step-by-step explanation:

We need to solve the linear equation

4b + 6 = 2 - 6 +4

Adding constants

4b + 6 = 0

Adding -6 on both sides

4b + 6 -6 = 0 -6

4b = -6

Dividing with 4 on both sides

4b/4 = -6/4

b = -2

So, the solution of linear equation 4b + 6 = 2 - 6 + 4 is b = -2

8 0
3 years ago
It takes Santa a total distance of 1800 miles to cover a portion of his
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2 years ago
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babunello [35]

Answer:

Answer A

Step-by-step explanation:

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8 0
4 years ago
Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9
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Parameterize C by

\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle

where 0\le t\le\pi. Then the line integral is

\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt
=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt
=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt

Take u=\cos t, then

=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du
=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du
=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du
=54
6 0
3 years ago
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