Given: AB || DC and m∠2 ≅ m∠4

LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

$\frac{a^{m}}{a^{n}}=a^{m-n},m>n\\\\\\\frac{a^{m}}{a^{n}}=\frac{1}{a^{m-n}}, m$

$\frac{5x^{4}y^{7}}{25xy^{10}}=\frac{5x^{4}y^{7}}{5^{2}xy^{10}}\\\\=\frac{x^{4-1}}{5^{2-1}*y^{10-7}}\\\\=\frac{x^{3}}{5y^{3}}$

2) $a^{m}*a^{n}=a^{m+n}$

$(-3x^{3}y^{5})(5xy^{-3})= -3*5 *x^{3+1}*y^{5-3}\\\\= -15x^{4}y^{2}$

3) $a^{-m}=\frac{1}{a^{m}}$

$\frac{24a^{4}b^{-3}}{16a^{-2}b}=\frac{3a^{4}b^{-3}}{2a^{-2}b}\\\\=\frac{3a^{4*a^{2}}}{2a^{-2}*b*b^{3}}\\\\=\frac{3a^{4+2}}{2b^{1+3}}\\\\=\frac{3a^{6}}{2b^{4}}$

4 0

3 years ago

I need help asap!!!!!!!!!!!!

eimsori [14]

Answer:

121 books

Step-by-step explanation:

bc that equals 11 so there are 11 squares plus the two missing ones from before so u do 11x11 which would be 121

hope this helps :>

5 0

3 years ago

Let X = the time between two successive arrivals at the drive-up window of a local bank. If X has an exponential distribution wi

Illusion [34]

Answer:

(a) $E(X) = 1$

(b) $\sigma_X =1$

(c) P(X ≤ 1) = 0.6321

(d) P(2 ≤ X ≤ 5) = 0.1286

Step-by-step explanation:

From the given information; Let consider X to be the time between two successive arrivals at the drive-up window of a local bank.

However; If X is regarded as the exponential distribution with λ = 1 which is identical to a standard gamma distribution with ∝ = 1

The objective is to compute the following :

(a) The expected time between two successive arrivals is;

$E(X) = \dfrac{1}{\lambda}$

$E(X) = \dfrac{1}{1}$

$E(X) = 1$

(b) The standard deviation of the time between successive arrivals is;

$\sigma_X = \sqrt{\dfrac{1}{\lambda^2}}$

$\sigma_X ={\dfrac{1}{\lambda}}$

$\sigma_X ={\dfrac{1}{1}}$

$\sigma_X =1$

(c) P(X ≤ 1)

P(X ≤ 1) = 1 - e⁻¹

P(X ≤ 1) = 0.6321

(d) P(2 ≤ X ≤ 5)

P(2 ≤ X ≤ 5) = [1 - e⁻⁵] - [1 - e⁻²]

P(2 ≤ X ≤ 5) = 0.9933 - 0.8647

P(2 ≤ X ≤ 5) = 0.1286

7 0

3 years ago

Using the cards 3,2,4,7 show a valua closest to 5000

zalisa [80]

4,7,3,2

Step-by-step explanation:

THESE ARE THE THE ARRANGEMENT OF NUMBERS IN ORDER TO GET THE CLOSEST TO 5000

4 0

2 years ago

Ten increased by the quotient of a number and 6 is 5

jonny [76]

Let the required number be x, then 10 + x/6 = 5
x/6 = 5 - 10 = -5
x = 6 x -5 = -30
x = -30

5 0

3 years ago

Given: ﻿AB || DC and m∠2 ≅ m∠4

Given: AB || DC and m∠2 ≅ m∠4