Answer:
360 learners
Step-by-step explanation:
One way to solve these types of problems is that you could set up a proportion
learners/teachers = learners/teachers
Let x = no. of learners to enrol
30/1 = x/12
12(30) = x
x = 360 learners
Answer:
2.447457627 x 10^6
Step-by-step explanation:
If this helped can i have Brainliest
Answer:
First, determine how many standard deviations above the mean one would have to be to be in the 75th percentile. This can be found by using a z table and finding the z associated with 0.75. The value of z is 0.674. Thus, one must be .674 standard deviations above the mean to be in the 75th percentile
Lwh=v
2*w*(w+2)=48
2w^2+4w=48
w^2+2w-24=0
(w+6)(w-4)=0
w= - 6 or w= 4
Since w cannot be negative, then w=4.
The correct answer is 21.5