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Margaret [11]
2 years ago
13

A landscaper makes a $2,000 profit in a week when he services 25 lawns. he makes a $600 profit in a week when he services 11 law

ns. if his profit for the week is a linear function of the number of lawns serviced, how much profit would he receive in a week that he services 36 lawns? $2,600 $2,880 $3,100 $3,600
Mathematics
1 answer:
aleksandrvk [35]2 years ago
4 0

Answer:

$3,100

Hope this helps!!

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2 45 is a common multiple of 5 and 9 true or false
Strike441 [17]

Answer:

False

Step-by-step explanation:

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2 years ago
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A polygon with 12 sides is called a/an <br> a. dodecagon. <br> b. pentagon. <br> c. undecagon.
Pepsi [2]
The answer is A. dodecagon.
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3 years ago
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The populations and land areas of four cities in Texas are shown. Which statements are true? Check all that apply. The populatio
galben [10]
Im pretty sure its A, D, and E
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4 years ago
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A number, X, rounded to 1 decimal place is 3,7<br> Write down the error interval for x,
sp2606 [1]

Answer:

The error interval for x is:

                 [3.65,3.74]

Step-by-step explanation:

The number after rounding off is obtained as:

                         3.7

We know that any of the number below on rounding off the number to the first decimal place will result in 3.7:

  3.65     3.66    3.67    3.68    3.69    3.70    3.71   3.72    3.73    3.74

( Because if we have to round off a number present in decimals to n place then if  there is a  number greater than or equal to 5 at n+1 place then it will result to the one higher digit  at nth place on rounding off and won't change the digit if it less than 5 )

        Hence, the error interval is:

            [3.65,3.74]

6 0
3 years ago
Two parts Someone please help!!!!!
aivan3 [116]

Answer:

Part one: The function rule for the area of the rectangle is A(x) = 3x² - 2x

Part two: The area of the rectangle is 8 feet² when its width is 2 feet

Step-by-step explanation:

Assume that the width of the rectangle is x

∵ The width of the rectangle = x feet

∵ The length of the rectangle is 2 ft less than three times its width

→ That means multiply the width by 3, then subtract 2 from the product

∴ The length of the rectangle = 3(x) - 2

∴ The length of the rectangle = (3x - 2) feet

∵ The area of the rectangle = length × width

∴ A(x) = (3x - 2) × x

→ Multiply each term in the bracket by x

∵ A(x) = x(3x) - x(2)

∴ A(x) = 3x² - 2x

∴ The function rule for the area of the rectangle is A(x) = 3x² - 2x

∵ The rectangle has a width of 2 ft

∵ The width = x

∴ x = 2

→ Substitute x by 2 in A(x)

∵ A(2) = 3(2)² - 2(2)

∴ A(2) = 3(4) - 4

∴ A(2) = 12 - 4

∴ A(2) = 8

∴ The area of the rectangle is 8 feet² when its width is 2 feet

5 0
3 years ago
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