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Irina-Kira [14]
4 years ago
10

Write an equation in slope-intercept form for a line that passes through points (-1, 2) and (5, -10)

Mathematics
1 answer:
sesenic [268]4 years ago
6 0
The equation is y= -12/6x
So negative 12 over 6 x^^
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What's 9 + 10? What's 1 + 1? What's 2 + 2? What's 9 * 9? What's 12 * 12? What's 8999000 * 4499000​
Vlad1618 [11]

Answer:9+10 is 19

1+1 is 2

2+2=4

9 * 9 is 81

12 * 12= 144

last one not sure

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the equation of the parabola, in vertex form, with focus at (1,-4) and<br> directrix x= 3?
lilavasa [31]

Answer:

D.

Step-by-step explanation:

1) according to the definition of parabola d(focus)=f(directrix),

2) then

d(focus)=\sqrt{(x-1)^2+(y+4)^2} \ and \ d(directrix)=|x-3|;

\sqrt{(x-1)^2+(y+4)^2} =|x-3|;

3) after evoluation the equation:

(y+4)²=-4x+8 or (y+4)²= -4(x-2);

4) correct answer is D.

3 0
3 years ago
Plz solve this problem of trigonometry<br>i am an aakashian​
makkiz [27]

Step-by-step explanation:

\bf L.H.S = \tt \dfrac{sec\: \theta + tan \:  \theta - 1}{tan \:  \theta - sec \:  \theta + 1}  \\  \\

:  \implies \tt \dfrac{\frac{1}{cos  \: \theta}  +  \frac{sin \:  \theta}{cos \: \theta}  - 1}{  \frac{sin \:  \theta}{cos \:  \theta} -  \frac{1}{cos \:  \theta} + 1   } \:  =   \dfrac{1 + sin \:  \theta - cos \:  \theta}{sin \: \theta + cos \:  \theta} \\  \\

: \implies \tt\dfrac{ sin \:  \theta - (cos \:  \theta - 1)}{sin \: \theta + (cos \:  \theta - 1)} \:  \times  \: \dfrac{ sin \:  \theta - (cos \:  \theta - 1)}{sin \: \theta  -  (cos \:  \theta - 1)} \\  \\

: \implies \tt\dfrac{ sin^{2}  \:  \theta  + cos^{2}  \:  \theta  + 1 - 2  \: cos \:  \theta  - 2  \: sin \:  \theta \: (cos \:  \theta - 1)}{sin^{2}  \: \theta  -  (cos \:  \theta - 1)^{2} } \\  \\

: \implies \tt\dfrac{1 + 1 - 2 \:  cos \:  \theta - 2 \: sin \:  \theta  \: cos \:  \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta - 1 + 2 \: cos \:  \theta } \\  \\

: \implies \tt\dfrac{2 - 2 \:  cos \:  \theta - 2 \: sin \:  \theta  \: cos \:  \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta  - sin^{2} \:  \theta - cos^{2}   \:  \theta  + 2 \: cos \:  \theta } \\  \\

: \implies \tt\dfrac{2 (1 - \:  cos \:  \theta )- 2 \: sin \:  \theta  (1 - \: cos \:  \theta)}{ 2 \: cos \: \theta - 2 \: cos^{2}   \:  \theta} \\  \\

: \implies \tt\dfrac{(2  +  2 \:  sin \:  \theta)  \:  \cancel{(1 -  cos\:  \theta)}}{2 \: cos \:  \theta  \:  \cancel{(1 - cos \:  \theta)}} \:  =  \:  \dfrac{1 + sin \:  \theta}{cos \: \theta}  \\  \\

: \implies\tt\dfrac{1 + sin \:  \theta}{cos \: \theta}  \:  \times  \: \dfrac{1  -  sin \:  \theta}{1 - sin \: \theta} \\  \\

:  \implies\tt\dfrac{1 + sin^{2}  \:  \theta}{cos \: (1 - sin \: \theta)} \\  \\

:  \implies\tt\dfrac{cos^{2}  \:  \theta}{cos \: \theta (1 - sin \: \theta)} \\  \\

:  \implies\tt\dfrac{cos \:  \theta}{1 - sin \: \theta}  \:  = \:  \bf{ R.H.S}\\  \\

\huge\bigstar  \:\underline{\red{\sf Hence, Proved}} \:  \bigstar \\

6 0
4 years ago
<img src="https://tex.z-dn.net/?f=%287%20-%208%29%20%5Ctimes%202%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="(7 - 8) \times 2
Diano4ka-milaya [45]
Answer: -4
Work: 7-8 = -1 x 4
7 0
3 years ago
Read 2 more answers
c) In the figure alongside, PQ = PR, PS QR, write down therelation between QS and SR, and angleQPS and angleRPS.​
bazaltina [42]

Answer:

QS=SR ( being PS median of triangle PQR,psㅗQR)

<QPS=<SPR (Median PS bisects the angle P)

HOPE THIS WILL HELP YOU...!

4 0
3 years ago
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