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kolbaska11 [484]
3 years ago
15

(Free points)Factorise x³ + 216y³ + 8z³ - 36xyz​

Mathematics
2 answers:
Sholpan [36]3 years ago
7 0

Answer:

im begging you not to report me instead just pls let me pass

Step-by-step explanation:

Nadusha1986 [10]3 years ago
3 0

Answer:

[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]

Step-by-step explanation:

x³+216y³+8z³-36xyz

x³+(6y)³+(2z)³-3×6×2×xyz

As we know

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

Let a=x

b=6y

c=2z

Now.

[x+6y+2z][(x²+(6y)²+(2z)²-x×6y-6y×2z-x×2z]

[x+6y+2z][x²+(6y)²+(2z)²-6xy-12yz-2xz]

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Answer:

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Step-by-step explanation:

17.8

To make this a faction

178/10

Divide by 2 on top and bottom

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4 0
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Step-by-step explanation:

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nata0808 [166]

So, since we have a cubic equation with 4 terms, the first thing we should try is factoring by grouping, so:

12x^3+2x^2-30x+5 =0 \implies \\ 2x^2(6x+1)-5(6x+1)=0 \implies \\ (2x^2-5)(6x+1) = 0

Now that we've factored our equation, we can use ZPP and break it up:

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Answer:

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