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Eddi Din [679]
3 years ago
7

In the formula a2 + b2 = c2, what is the value of a2?

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
6 0
A^2 + b^2 = c^2 Moving b^2 to RHS a^2 = c^2 - b^2
eimsori [14]3 years ago
4 0
a^2+b^2=c^2\ \ \ \ |subtract\ b^2\ from\ both\ sides\\\\a^2=c^2-b^2\\\\\boxed{a=\sqrt{c^2-b^2}}
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The course grade in a statistics class is the average of the scores on five examinations. Suppose that a student's scores on the
nadya68 [22]

Answer:

84 is the highest possible course average

Step-by-step explanation:

Total number of examinations = 5

Average = sum of scores in each examination/total number of examinations

Let the score for the last examination be x.

Average = (66+78+94+83+x)/5 = y

5y = 321+x

x = 5y -321

If y = 6, x = 5×6 -321 =-291.the student cannot score -291

If y = 80, x = 5×80 -321 =79.he can still score higher

If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.

If y= 100

The average cannot be 100 as student cannot score 179(maximum score is 100)

8 0
3 years ago
Simplify the algebraic expression: (Combine like terms)<br><br> 25 + 3x + 16y - 15 + x - 10y
Maslowich
10+4x+6y because 25-15 3+1 and 16-10
4 0
3 years ago
Read 2 more answers
WHY CAN'T ANYONE HELP ME? :( Jen Butler has been pricing​ Speed-Pass train fares for a group trip to New York. Three adults and
devlian [24]

Answer:

Children: $13

Adults: $18

Step-by-step explanation:

Well for both sets we can set up the following system of equations,

\left \{ {{3a + 4c = 106} \atop {2a + 3c = 75}} \right.

So first we need to solve for a in the first equation.

3a + 4c = 106

-4c to both sides

3a = -4c + 106

Divide 3 by both sides

<u>a = -4/3c + 35 1/3</u>

Now we plug in that a for a in 2a + 3c = 75.

2(-4/3c + 35 1/3) + 3c = 75

-8/3c + 70 2/3 + 3c = 75

Combine like terms

1/3c + 70 2/3 = 75

-70 2/3 to both sides

1/3c = 4 1/3

Divide 1/3 to both sides

c = 13

Now we can plug in 13 for c in 3a + 4c = 106,

3a + 4(13) = 106

3a + 52 = 106

-52 to both sides

3a = 54

Divide 3 by both sides.

a = 18

<em>Thus,</em>

<em>an adult ticket is $18 and a children's ticket is $13.</em>

<em />

<em>Hope this helps :)</em>

5 0
3 years ago
Read 2 more answers
One of the solutions of the system of equations shown in the graph has an x-value of –4. What is its corresponding integer y-val
jeka57 [31]
The solution is (-4, -1
7 0
3 years ago
Read 2 more answers
Please help me and If your answer is wrong or not appropreat I will report it
arsen [322]

Answer:

972 x^16 y^24

Step-by-step explanation:

Simplify the following:

(-2 x^3 y^7)^2 (3 x^2 y^2)^5

Multiply each exponent in -2 x^3 y^7 by 2:

(-2)^2 x^(2×3) y^(2×7) (3 x^2 y^2)^5

2×7 = 14:

(-2)^2 x^(2×3) y^14 (3 x^2 y^2)^5

2×3 = 6:

(-2)^2 x^6 y^14 (3 x^2 y^2)^5

(-2)^2 = 4:

4 x^6 y^14 (3 x^2 y^2)^5

Multiply each exponent in 3 x^2 y^2 by 5:

4 x^6 y^14×3^5 x^(5×2) y^(5×2)

5×2 = 10:

4×3^5 x^6 y^14 x^(5×2) y^10

5×2 = 10:

4×3^5 x^6 y^14 x^10 y^10

3^5 = 3×3^4 = 3 (3^2)^2:

4×3 (3^2)^2 x^6 y^14 x^10 y^10

3^2 = 9:

4×3×9^2 x^6 y^14 x^10 y^10

9^2 = 81:

4×3×81 x^6 y^14 x^10 y^10

3×81 = 243:

4×243 x^6 y^14 x^10 y^10

4 x^6 y^14×243 x^10 y^10 = 4 x^(6 + 10) y^(14 + 10)×243:

4×243 x^(6 + 10) y^(14 + 10)

14 + 10 = 24:

4×243 x^(6 + 10) y^24

6 + 10 = 16:

4×243 x^16 y^24

4×243 = 972:

Answer: 972 x^16 y^24

8 0
2 years ago
Read 2 more answers
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