All categories

3 years ago

How many different triangles can you make with 14cm, 10cm and 50cm sides?

Mathematics

2 answers:

Dominik [7]3 years ago

7 0

Answer:

Step-by-step explanation:

ANEK [815]3 years ago

5 0

Hello from MrBillDoesMath!

Answer:

0 (zero)

Discussion:

From the "triangle inequality", the sum of any two sides of a traingle must be greater than the length of the third side. As 14 + 10 is not greater than (is less than) 50, o no such triangle exists

Thank you,

MrB

You might be interested in

Which is the correct label of the parallel lines? parallel lines a and b are shown. points a and b lie on line a while points c

Nataly_w [17]

It might be b and d because there not touching

3 0

3 years ago

Read 2 more answers

26. A(-4, -1), B(-4, 6), C(2,6), D(2, -4)

Fudgin [204]

Answer:

I NEEEEEEEED TO SEEEE GRAPHHHHHHHHHHHH

Step-by-step explanation:

5 0

2 years ago

Consider the following system of equations:

Delicious77 [7]

Answer:

The system has infinitely solutions

Step-by-step explanation:

we have

$-\frac{1}{3}x^{2}=-\frac{5}{6}+\frac{1}{3}y^{2}$

$\frac{1}{3}x^{2}+\frac{1}{3}y^{2}=\frac{5}{6}$

Multiply by 3 both sides

$x^{2}+y^{2}=\frac{5}{2}$ ----> equation A

The equation A is a circle centered at origin with radius $r=\sqrt{5/2}\ units$

and

$5y^{2} =\frac{25}{2}-5x^{2}$

$5x^{2}+5y^{2} =\frac{25}{2}$

Divide by 5 both sides

$x^{2}+y^{2} =\frac{5}{2}$ ----> equation B

The equation B is a circle centered at origin with radius $r=\sqrt{5/2}\ units$

Equation A and Equation B are the same

Therefore

The system has infinitely solutions

7 0

3 years ago

Read 2 more answers

The hypotenuse of a right triangle measures 58 cm and one of its legs measures 42 cm. What is the length of the missing leg? 10

Nutka1998 [239]

If the hypotenuse is 58cm, and one of the others legs is 42cm the answer would be 40cm

Explanation:

Here you have to use the formula

${a}^{2} + {b}^{2} = {c}^{2}$
Then you have to pose the formula in terms of one of the legs, so:

${a}^{2} = {c}^{2} - {b}^{2}$
$a = \sqrt{ {c}^{2} - {b}^{2}}$
So when you change the letter for numbers you have that:

$a = \sqrt{ {58}^{2} - {42}^{2} }$

a=40

5 0

3 years ago

What is the simplest form of the radical expression 8?

Kisachek [45]

The answer oils be 2 square root 2 because 4 times 2 is 8 and because the square root of 4 is 2 you would move that 2 to the outside and keep the other two on the inside of the square root.

5 0

3 years ago