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sweet [91]
3 years ago
14

write an equation that is perpendicular to x - 3y =3 and passes through the point (5,-9) in slope-intercept form.

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

9514 1404 393

Answer:

  y = -3x +6

Step-by-step explanation:

The perpendicular line will have the coefficients of x and y swapped (and one of them negated), and will have a constant appropriate to the point the line needs to go through.

The equation will look like ...

  x -3y = 3 . . . . . . . . . . . . . given line

  3x +y = constant . . . . . . perpendicular line

where "constant" can be found by substituting for x and y.

  3x +y = 3(5) +(-9)

  3x +y = 6 . . . . equation in standard form

To put this in slope-intercept form subtract 3x:

  y = -3x +6

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A pair of boots that originally sold for $75.32 are on sale for 22% off.
Vesnalui [34]

Answer:

The boots will be $58.75

Step-by-step explanation:

first you cross multiply

\frac{x}{75.32} x \frac{22}{100}

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2 years ago
Help please. <br> Give the slope of y - 3 = 4(x + 8) and a point on the line
Sauron [17]
-----------------------------------------------------------
Make y the subject :
-----------------------------------------------------------
y - 3 = 4(x + 8)      
y - 3 = 4x + 32           // Apply distributive property
y = 4x + 35                // Add 3 to both sides

-----------------------------------------------------------
Identify Slope : 
-----------------------------------------------------------
Slope = 4

-----------------------------------------------------------
Find a point on the line :
-----------------------------------------------------------
When x = 0, 
y = 4(0) + 35              // Sub x = 0 into the equation 
y = 35                         // Combine like terms
Point = (0, 35)

-----------------------------------------------------------
Answers :
(a) Slope = 4
(b) One point on the line is (0, 35)
-----------------------------------------------------------
4 0
3 years ago
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