Question

write an equation that is perpendicular to x - 3y =3 and passes through the point (5,-9) in slope-intercept form.

Answer 1

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Answer:

  y = -3x +6

Step-by-step explanation:

The perpendicular line will have the coefficients of x and y swapped (and one of them negated), and will have a constant appropriate to the point the line needs to go through.

The equation will look like ...

  x -3y = 3 . . . . . . . . . . . . . given line

  3x +y = constant . . . . . . perpendicular line

where "constant" can be found by substituting for x and y.

  3x +y = 3(5) +(-9)

  3x +y = 6 . . . . equation in standard form

To put this in slope-intercept form subtract 3x:

  y = -3x +6