The diagonals of a rhombus are of length 24cm and32cm.

Ipatiy [6.2K]

The expression to evaluate is 32 + (8 - 2) * 4 - 6/3. In the first step you can solve the parenthesis and the fraction => 32 + (6)*4 - 2. In the second step you mutiply 6*4 => 32 + 24 - 2. Finally, you do the maths: 32 + 24 - 2 = 54. Answer: 54

8 0

3 years ago

9) Is 0 a solution to 3x + 8 = 5x + 8? Explain or show your reasoning .

alex41 [277]

Answer:

x=0, yes.

Step-by-step explanation:

3x+8=5x+8

5x-3x+8=8

2x+8=8

2x=8-8

2x=0

x=0/2

x=0

4 0

3 years ago

Read 2 more answers

Suppose you are traveling straight from Los Angeles, California to Albuquerque, New Mexico, stopping overnight in Flagstaff, Ari

Roman55 [17]

D. L.A. to Flagstaff, 465 miles; Flagstaff to Albuquerque, 345 miles

The answer above is correct.

810 - 120 = 690 ; 690 / 2 = 345 mi ( Flagstaff to Albuquerque )

810 - 345 = 465 mi ( L.A. to Flagstaff )

3 0

3 years ago

A cereal box says that now it contains 20% more. Originally, it came with 20 ounces of cereal. How much cereal does the box come

Novosadov [1.4K]

Answer:24ounces

Step-by-step explanation:

Multiply 20 ounces by .20 (The percent) then add your answer to the 20 ounces.

6 0

3 years ago

You are given the information that P(A) = 0.30 and P(B) = 0.40.

Ad libitum [116K]

Answer:

1.B. No. You need to know the value of P(A and B). 2.C. Yes P(A and B) =0, so P(A or B) = P(A) + P(B).

Step-by-step explanation:

We can solve this question considering the following:

For two mutually exclusive events:

$\\ A_{1}\;and\;A_{2}$

$\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2})$ (1)

An extension of the former expression is:

$\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1} and A_{2})$ (2)

In mutually exclusive events, P(A and B) = 0, that is, the events are independent one of the other, and we know the probability that both events happen at the same time is zero (P(A and B) = 0). There are some other cases in which if event A happens, event B too, so they are not mutually exclusive because P(A and B) is some number different from zero. Notice the difference between OR and AND. The latter implies that both events happen at the same time.

In other words, notice that the formula (2) provides an extension of formula (1) for those events that are not mutually exclusive, that is, there are some cases in which the events share the same probabilities in a way that these probabilities must be subtracted from the total, so those probabilities in common do not "inflate" the actual probability.

For instance, imagine a person going to a gas station and ask for checking both a tire and lube oil of his/her car. The probability for checking a tire is P(A)=0.16, for checking lube oil is P(B)=0.30, and for both P(A and B) = 0.07.

The number 0.07 represents the probability that both events occur at the same time, so the probability that this person ask for checking a tire or the lube oil of his/her car is:

P(A or B) = 0.16 + 0.30 - 0.07 = 0.39.

That is why we cannot simply add some given probabilities without acknowledging if the events are or not mutually exclusive, whereas we can certainly add the probabilities in question when we know that both probabilities are mutually exclusive since P(A and B) = 0.

In conclusion, knowing the events are mutually exclusive does provide extra information and we can proceed to simply add the probabilities of either event; thus, the answers are those in which we need to previously know the value of P(A and B).

7 0

3 years ago