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3 years ago

7

M.c.m (35;50)m.c.d (35;50)m.c.m (116;92)m.c.d (116;92)

1 answer:

Valentin [98]3 years ago

7 0

Answer:

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Two cars leave a town at the same time heading in opposite directions. One car is traveling 12 mph faster than the other. After

Katena32 [7]

<span>Find the speed of each car.
Let a be the first car
Let b be the second car
=> a = x miles per hour
=> b = x + 12 miles per hour
=> 2 (x+ x + 12) = 232 miles per hour
=> 2x + 12 = 232
=> 2x + 12 = 116
=> 2x = 116 - 12
=> 2x / 2 = 104 / 2
=> x = 52 (speed of Car A)
=> 52 + 12 = 64 miles per hour (speed of Car B)</span>

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3 years ago

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77julia77 [94]

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3 years ago

At the Sunnyvale Play House, the price for an adult ticket is $12 and the price of a child's ticket is $6. For Saturday night's

Rzqust [24]

Answer:

a + c = 125 & 12a + 6c = 1140

Step-by-step explanation:

adult ticket total + child ticket total = 125 total tickets

($12 x adult ticket total) + ($6 x child ticket total) = $1140

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3 years ago

Solve for X: Correctly answer the question

Klio2033 [76]

Answer:

x=16

Step-by-step explanation:

(whole secant) x (external part) = (tangent)^2

(8+24) * 8 = x^2

32*8 = x^2

256 =x^2

Take the square root of each side

sqrt(256) = sqrt(x^2)

16 = x

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2 years ago

Determine the equation of the circle graphed below.

sergij07 [2.7K]

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

<u>Find the centre of the circle.</u>

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

$Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})$

$=(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)$

<u>Find the radius of the circle.</u>

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

$Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}$

$=\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6$

Therefore,

$Radius ,r = \frac{6}{2} = 3$

<u>Standard equation of a circle:</u>

<u></u> $(x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.$ <u></u>

Therefore , equation of the circle ;

$(x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9$

6 0

3 years ago