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3 years ago

Could somebody help me please

Mathematics

1 answer:

pantera1 [17]3 years ago

7 0

Answer:

its 7

Step-by-step explanation:

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Use the form |x-b|<=c or |x-b|>=c to write an absolute value inequality that has the solution set -1<=x<=3.

IgorLugansk [536]

Answer:

Your answer would be:
X = -4

-1 <= -4 <= 3.

Step-by-step explanation:

Have a great rest of your day
#TheWizzer

8 0

2 years ago

Michael bought 0.65 kilograms of cubed stake. The meat costs $8.50 a kilogram. How much did Michael pay for the stake

Temka [501]

Answer:

Approximately $5.53

Step-by-step explanation:

You need to multiply the cost of meat per kilogram by the amount you you buy in kilograms.

$8.50*0.65= $5.525

That rounds to $5.53

8 0

3 years ago

Hello:) I Hope your having a good day :)),Im NOOOOT MY STOMCAH HURTS SO BAD:(((((

steposvetlana [31]

Answer:

oh noooooooooooooo

Step-by-step explanation:

take this (*￣3￣)╭

5 0

3 years ago

Read 2 more answers

Help please no links and not bots

goldfiish [28.3K]

Answer:

75=5*3*5

Step-by-step explanation:

5*3=15

15*5=75

5 0

3 years ago

If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?

Keith_Richards [23]

$\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}$

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

$\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}$

so, the domain is all real numbers EXCEPT that one.

4 0

3 years ago