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Snowcat [4.5K]
3 years ago
7

At the deli counter, Marisol orders 740 grams of ham, 520 grams of turkey, and half as much roast beef as ham. What is the total

mass in kilograms of Marisol's order?
Mathematics
1 answer:
Alenkasestr [34]3 years ago
6 0

Answer:

1.63 Kilograms

Step-by-step explanation:

I started by finding out what the roast beef weighed. Then I added 740, 520, and 370 (what the roast beef weighs). I can work that way because they are all in grams. The total off all that equals 1630 grams. Then I converted that to kilograms. Which will end up giving you 1.63 kilograms.

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A 1/4 lb package of sunflower seeds cost 79cents. An 8 ounces package cost 1.59. Which package represents the lower cost per oun
arsen [322]
The first package is 4 oz (1/4lb) at 79cents = 19.75 cents/oz
Second Package is 8 oz at 1.59 = 19.875 cents / oz
So the first package is cheaper per ounce.
6 0
4 years ago
The Insurance Institute reports that the mean amount of life insurance per household in the US is $110,000. This follows a norma
nata0808 [166]

Answer:

a) \sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85

b) Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

c) P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)

And we can use the complement rule and we got:

P(Z>0.354) = 1-P(Z

d) P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)

And we can use the complement rule and we got:

P(Z>-1.768) = 1-P(Z

e) P(100000< \bar X

And we can use the complement rule and we got:

P(-1.768

Step-by-step explanation:

a. If we select a random sample of 50 households, what is the standard error of the mean?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the amount of life insurance of a population, and for this case we know the distribution for X is given by:

X \sim N(110000,40000)  

Where \mu=110000 and \sigma=40000

If we select a sample size of n =35 the standard error is given by:

\sigma_{\bar X} = \frac{\sigma}{\sqrt{n}}= \frac{40000}{\sqrt{50}}= 5656.85

b. What is the expected shape of the distribution of the sample mean?

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

c. What is the likelihood of selecting a sample with a mean of at least $112,000?

For this case we want this probability:

P(X > 112000)

And we can use the z score given by:

z= \frac{\bar X  -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

P( \bar X >112000) = P(Z>\frac{112000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>0.354)

And we can use the complement rule and we got:

P(Z>0.354) = 1-P(Z

d. What is the likelihood of selecting a sample with a mean of more than $100,000?

For this case we want this probability:

P(X > 100000)

And we can use the z score given by:

z= \frac{\bar X  -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

P( \bar X >100000) = P(Z>\frac{100000-110000}{\frac{40000}{\sqrt{50}}}) = P(Z>-1.768)

And we can use the complement rule and we got:

P(Z>-1.768) = 1-P(Z

e. Find the likelihood of selecting a sample with a mean of more than $100,000 but less than $112,000

For this case we want this probability:

P(100000

And we can use the z score given by:

z= \frac{\bar X  -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

P(100000< \bar X

And we can use the complement rule and we got:

P(-1.768

8 0
4 years ago
What is the slope ? M=
frez [133]

Answer:

-3/2

Step-by-step explanation:

The slope is found by

m = ( y2-y1)/(x2-x1)

Using the points (-4,11) and ( 0,5)

m = ( 11-5)/( -4-0)

  = 6/-4

  = -3/2

4 0
3 years ago
Olivia attempted to construct a circle circumscribed about a triangle, but the circle only passed through one of the three verti
sleet_krkn [62]
When <span>constructing a circle circumscribing about a triangle, we bisect any two lines and not angles. 
It is not necessary to bisect the three sides.
The most logical mistake the learner could have made are:
</span><span>A. The compass involuntarily changed the radius setting when drawing circle and</span> 
<span>C. The altitudes were constructed incorrectly.</span>
3 0
3 years ago
11. A quiz has 10 multiple choice questions with 3 choices for each question. Answer the following for someone who randomly choo
11111nata11111 [884]

The required probability for
a. 0.2058
b. 0.98  
c.0.016

<h3>
What is probability?</h3>

Probability can be defined as the ration of favorable outcomes to the total number of events.

Let use binomial distribution.
Probability answering a question correctly=1/3 =0.33
Probability of not answering a question correctly
=1–1/3
=2/3
a) Out of 10 probability of answering 4 correctly

=10c4 x (0.33)^4 x (0.66)^6

Upon simplification, 0.2058

b) Find the probability for getting at least 2 correct answers
= 1 - { 10c8 x (0.33)^8 x (0.66)^2+ 10c9 x (0.33)^9 x (0.66)^1 + (0.33)^10}
= 0.98

c).Find the probability for getting 2 or 3 incorrect answers.


10c8 x (0.33)^8 x (0.66)^2 + 10c7 x (0.33)^7 X (0.66)^3
=0.002 + 0.014

= 0.016

Thus the required probabilities are: 0.2058, 0.98 , 0.016

Learn more about probability here:

brainly.com/question/14290572

#SPJ1


4 0
2 years ago
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