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3 years ago

What is the result of this subtraction?

Mathematics

2 answers:

a_sh-v [17]3 years ago

8 0

6.3 - (4.9 - 7.8)
6.3 - 4.9 + 7.8
1.4 + 7.8
9.2

Answer:
D) 9.2

uysha [10]3 years ago

4 0

Answer: 9.2

Step-by-step explanation:

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What does AD equal? PICTURE INCLUDED* Triangle congruence and similarity.

mafiozo [28]

Answer:

AD = 7

Step-by-step explanation:

Given that the two triangles are similar by the SSS (side side side) postulate, the triangles share the same ratios when it comes to their sides.

We know the values for lines DB, EB and CB, therefore we can solve for AB, and subtract DB to find AD

We can solve the problem by solving for x:

$\frac{x}{32} =\frac{21}{24}$

Cross multiply.

$24x = 672$

Simplify.

$x=28$

Subtract the value of DB to find AD.

$28-21=7$

$AD=7$

8 0

3 years ago

How can I find the area and perimeter of the circle? pls help

strojnjashka [21]

The perimeter of the circle is also known as the circumference that said figure out what the diameter is and multiply that by pi (3.14)

8 0

3 years ago

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Two students walk in the same direction along a straight path, at a constant speed - one at .90 m/s and the other at 1.90 m/s.a.

anyanavicka [17]

Answer:

a)The second student arrive 7 minutes and 36 seconds sooner

b)They have to walk 598,51 m

Step-by-step explanation:

Speed= Distance/Time

We are looking for time now

Time = Distance/Speed

First student

Time = 780 m/0.90 m/s=866,66 seconds

Second student

Time = 780 m/1.90 m/s=410,52 seconds

Difference=866,66-410,52= 456,14 seconds

In minutes

Difference= 456,14 seconds /60=7 minutes 36 seconds

Distance=Speed x Time

Speed¹ x Time¹ =Speed² x Time²

Time¹= Time² + 5.50 min

5.50 min =350 seconds

Time² =Speed¹ x Time¹ /Speed²

Time² =Speed¹ x (Time² + 350 seconds ) /Speed²

Time² =0.9 x (Time² + 350 seconds ) /1.9

Time² =0,4737 x (Time² + 350 seconds )

Time² =0,4737 Time² + 165,79 seconds

Time² - 0,4737 Time² = 165,79 seconds

0,5263 Time² = 165,79 seconds

Time² = 165,79 seconds/0,5263 =315,01 seconds

Distance=1,9 x 315,01 seconds = 598,51 m

5 0

3 years ago

Solve using long division <br> Please

madreJ [45]

1. $Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}$

$Steps:$

$\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}$

$\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}$

$\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}$

$\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}$

$\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}$

2. $Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}$

$Steps:$

$\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}$

$\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}$

$\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

4 0

3 years ago

What is the answer to (5x3)-18

Fittoniya [83]

Answer:

-3

Step-by-step explanation:

5*3=15

15-18= -3

5 0

3 years ago

Read 2 more answers