Answer:
inches and
inches.
Step-by-step explanation:
Let x and y represent sides of the poster.
We have been given that a poster has an area of 240 in². We can represent this information in an equation as:

The side of new poster with 1-inch margin on sides would be
and 2 inch margin on top and 1 inch margin at the bottom would be
.
The area of new poster would be
.
Upon substituting
in area equation, we will get:



Since, we need to maximize the area, so we will find critical points.
First of all, we will find derivative of area function as:


Now, we will equate derivative with 0 to find critical values:








Since length cannot be negative, therefore, side length would be
.


Therefore, side length of
inches and
inches will give the largest printed area.