So when this sign < has a line under the greater sign so this mean greater or equal
same with this
12>= x so this mean 12 greater or equal x but than there is a line under the greater sign so this mean equalitie sure too
hope this will help you
Answer:
c
Step-by-step explanation:
Here's how this works:
Get everything together into one fraction by finding the LCD and doing the math. The LCD is sin(x) cos(x). Multiplying that in to each term looks like this:
![[sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?](https://tex.z-dn.net/?f=%5Bsin%28x%29cos%28x%29%5D%5Cfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%2B%5Bsin%28x%29cos%28x%29%5D%5Cfrac%7Bcos%28x%29%7D%7Bsin%28x%29%7D%20%3D%3F)
In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:
![\frac{sin^2(x)}{sin(x)cos(x)}+\frac{cos^2(x)}{sin(x)cos(x)}=?](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%5E2%28x%29%7D%7Bsin%28x%29cos%28x%29%7D%2B%5Cfrac%7Bcos%5E2%28x%29%7D%7Bsin%28x%29cos%28x%29%7D%3D%3F)
Put everything over the common denominator now:
![\frac{sin^2(x)+cos^2(x)}{sin(x)cos(x)}=?](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%5E2%28x%29%2Bcos%5E2%28x%29%7D%7Bsin%28x%29cos%28x%29%7D%3D%3F)
Since
, we will make that substitution:
![\frac{1}{sin(x)cos(x)}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bsin%28x%29cos%28x%29%7D)
We could separate that fraction into 2:
×![\frac{1}{cos(x)}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bcos%28x%29%7D)
and ![\frac{1}{cos(x)}=sec(x)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bcos%28x%29%7D%3Dsec%28x%29)
Therefore, the simplification is
sec(x)csc(x)
D= diagonal= 25 in
w= 15 in
A= w√(d^2﹣w^2)
A= (15)√(25^2 - 15^2)
square in parentheses
A= (15)√(625 - 225)
subtract in parentheses
A= (15)√(400)
take square root of 400
A= (15)(20)
A= 300 in^2
ANSWER: The area is 300 inches squared
Hope this helps! :)