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3 years ago

7

What is the volume of the cylinder below?

2 answers:

ella [17]3 years ago

5 0

Answer:

B) Volume of cylinder is $36 \pi$ units³.

Step-by-step explanation:

Given : Cylinder.

To find : what is the volume of the cylinder below.

Solution : We have given cylinder with radius = 3 units.

Height = 4 units .

Volume of cylinder = $\pi * radius^{2} * height.$

Plug the values

Volume of cylinder = $\pi * (3)^{2} * 4$ .

Volume of cylinder = $\pi* 9 * 4$ .

Volume of cylinder = $\pi 36$ units³.

Volume of cylinder is $36 \pi$ units³.

Therefore, B) Volume of cylinder is $36 \pi$ units³.

Anestetic [448]3 years ago

3 0

Answer:

B

Step-by-step explanation:

The formula for volume of cylinder is given below:

volume of cylinder = $\pi r^2 h$

Where r is the radius (here, it is given as 3)

h is the height, the perpendicular distance from base to top (here, it is 4 NOT 5 since 5 is the 'slant height')

Plugging in the available info , we get our answer:

$\pi r^2 h\\=\pi (3)^2 (4)\\=36\pi$

B is the correct answer

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City A grows by 5% every year. In 2021, it has a population of 145,201. What will the population be in 2037?

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Answer:

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Step-by-step explanation:

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3 years ago

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Explanation

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Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us

grigory [225]

Answer:

The confidence interval on this case is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

$\bar X = \frac{62.532+76.478}{2}= 69.505$

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma$ represent the population standard deviation

n represent the sample size

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The confidence interval on this case is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

$\bar X = \frac{62.532+76.478}{2}= 69.505$

So then the mean for this case is 69.505

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3 years ago