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2 years ago

What is 12x÷6x^2 please help

Mathematics

1 answer:

puteri [66]2 years ago

5 0

Answer:

I think it would be 4x

Step-by-step explanation:

Heres how. At first you ignore the exponent (you'll come back to it) 12x ÷ 6x = 2x. Then you have to solve with the exponent. 2 × 2 = 4 then add the label. 4x, and that's how you get the answer. Hope this helps.

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Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago

What is the length of AB? round to the nearest tenth

inna [77]

Answer:

theres nothing attached

Step-by-step explanation:

8 0

3 years ago

Help please.........

Lunna [17]

I am not sure, but the answer is probably option A. Graph A.

5 0

3 years ago

|3O+(-17)| I REALLY NEED TO KNOW PLZZZZZ

Soloha48 [4]

✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽

➷ $30 + 17$

➷ $30 + -17$

➷ $= 13$

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ May ♡

4 0

3 years ago

Read 2 more answers

X * 3 < 5 <br> solve for x

Nezavi [6.7K]

Answer:

the answer is X<5/3 correct me if i'm wrong

Step-by-step explanation:

hope this helps

3 0

3 years ago