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3 years ago

11

Every other weekend,Bronwyn Brother Danial mows the lawn. He can mow 15,000ft2 in 3/4 hour. who mows the lawn in less time? plea

se i hate algbra IT SUCKS

2 answers:

lidiya [134]3 years ago

8 0

You need to provide more context because the context you provided isn’t enough sorry.

ivann1987 [24]3 years ago

7 0

Answer:

you left something out but you need to put it in a better understanding

Step-by-step explanation:

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A wholesale distributor of packaged nuts sells two different mixes of peanuts and cashews, mix A and mix B. Each package of mix

jeka57 [31]

Answer:

b

Step-by-step explanation:

7 0

2 years ago

A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, $q_1 = Q- r \times Q$

$q_1 = Q(1-r)\cdots(i)$

The value of quantity after 2 months, $q_2 = q_1- r \times q_1$

$q_2 = q_1(1-r)$

From equation (i)

$q_2=Q(1-r)(1-r) \\\\q_2=Q(1-r)^2\cdots(ii)$

The value of quantity after 3 months, $q_3 = q_2- r \times q_2$

$q_3 = q_2(1-r)$

From equation (ii)

$q_3=Q(1-r)^2(1-r)$

$q_3=Q(1-r)^3$

Similarly, the value of quantity after n months,

$q_n= Q(1- r)^n$

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

$q_{48}=Q(1-r)^{48}$

Putting Q=6200 and r=5.5%=0.055, we have

$q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32$

Hence, the value of quantity after 4 years is 410.32.

4 0

2 years ago

Read 2 more answers

Find the probability that a point chosen at random will lie in the shaded region.

malfutka [58]

Step-by-step explanation:

In the 1st question

Total boxes = 6

Shaded boxes = 2

Probability = 2/6 = 1/3

5 0

2 years ago

Help help please please help hurry ASAP

labwork [276]

1. (2,-1)

2. (1.5,4)

3. (-2,3)

4. (1,4)

5. (0,3)

6. 5,4

7. 0,4

8. -1,-1

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3 years ago

Two step equations

Llana [10]

28 each book 155-15=140 and then 140÷5=28

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2 years ago