A sample of tennantite with mass of 2370 g contains 19.23 mol Cu.
You must make the following conversions:
Mass of tennantite → moles of tennantite → moles of Cu
<em>Step 1</em>. Calculate the <em>moles of tennantite</em> (Tn)
The <em>ideal </em>chemical formula of Tn is Cu_12As_4S_13.
Molar mass = (12×63.55 + 4×74.92 + 13×32.06) g/mol
= (762.60 + 299.68 + 416.78) g/mol = 1479.06 g/mol
Moles of Tn = 2370 g Tn × (1 mol Tn/1479.06 g Tn) = <em>1.60 24 mol Tn
</em>
<em>Step 2</em>. Calculate the <em>moles of Cu</em>
Moles of Cu = 1.6024 mol Tn × (12 mol Cu/1 mol Tn) = 19.23 mol Cu
O iodine (I) because scientists use it for a lot of experiments
There are 45.0009329 grams in 0.77 moles of NaCl
Hello!
* First Step: to know Avogrado's Law
We know that by the Law of Avogrado, for each mole of substance we have 6.02*10²³ atoms, if:
** Second Step: to know the molar mass of the solute
The molar mass of of magnesium = 24.30 g/mol
*** Third step: make the ratio mass / mol with atoms
1 mol we have 6.02*10²³ atoms
1 mole of Mg we have 24.30 g
Then we have:
24.30 g ------------- 6.02*10²³ atoms
x ----------------------- 6.98*10^24 atoms
multiply cross
I Hope this helps, greetings ... DexteR! =)
Answer:
27.99 dm³
Explanation:
Applying
PV = nRT................ Equation 1
Where P = Pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.
From the question, we were aksed to find V.
Therefore we make V the subject of the equation
V = nRT/P................ Equation 2
Given: n = 1.31 moles, T = 37°C = 310K, P = 904 mmHg = (904×0.001316) = 1.1897 atm
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
V = (1.31×310×0.082)/(1.1897)
V = 27.99 dm³