Given:
No of atoms present= 8.022 x 10^23 atoms
Now we know that 1 mole= 6.022 x 10^23 atoms
Hence number of moles present in 8.022 x 10^23 atoms is calculated as below.
Number of moles
= 8.022 x 10^23/6.022x 10^23
=1.3 moles.
Hence we have 1.3 moles present.
Answer:
0.18 mol
Explanation:
Given data
- Mass of carbon tetrachloride (solvent): 750 g
- Molality of the solution: 0.24 m
- Moles of iodine (solute): ?
Step 1: Convert the mass of the solvent to kilograms
We will use the relationship 1 kg = 1,000 g.

Step 2: Calculate the moles of the solute
The molality is equal to the moles of solute divided by the kilograms of solvent. Then,

carbon, hydrogen, oxygen, and nitrogen are the most important elements!
Answer:
- nitrogen
Explanation:
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