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user100 [1]
3 years ago
10

The following reaction was carried out in a 3.25 L reaction vessel at 1100 K:

Chemistry
1 answer:
kipiarov [429]3 years ago
3 0

Answer : The value of reaction quotient Q is, 0.498

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

C(s)+H_2O(g)\rightarrow CO(g)+H_2(g)

The expression for reaction quotient will be :

Q=\frac{[CO][H_2]}{[H_2O]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now we have to calculate the concentration of H_2O,CO\text{ and }H_2

\text{Concentration of }H_2O=\frac{\text{Moles of }H_2O}{\text{Volume of solution}}=\frac{13.3mol}{3.25L}=4.09M

and,

\text{Concentration of }CO=\frac{\text{Moles of }CO}{\text{Volume of solution}}=\frac{3.40mol}{3.25L}=1.05M

and,

\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{6.30mol}{3.25L}=1.94M

Now put all the given values in the above expression, we get:

Q=\frac{(1.05)\times (1.94)}{(4.09)}=0.498

Thus, the value of reaction quotient Q is, 0.498

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