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Effectus [21]
3 years ago
14

Question 23 of 25

Mathematics
1 answer:
ANTONII [103]3 years ago
6 0

Answer: m

Step-by-step explanation:

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James and Simon have a reading assignment to complete. James has read r
Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

125 I think

7 0
2 years ago
Read 2 more answers
YA
irakobra [83]

Answer:

a) P(0, <u>2</u>), Q(<u>4</u>, 0)

b) Please find attached the plot of the points P and Q on a chart made with MS Excel

c) Please find the graph of the line that represent the function 4·x + 2·y = 8 for values of x from -2 to 3 made with the Insert Chart feature on MS Excel

Step-by-step explanation:

The given equation for the line is 4·x + 2·y = 8

a) The coordinates of P = P(0, _)

Therefore, the point 'P', which is the point where the variable y = 0, is the point the (straight line) graph intercepts the x-axis (the x-intercept)

When y = 0 from the given equation, we get;

4·x + 2·y = 8

At the point y = 0;

4·x + 2 × 0 = 8

x = 8/4 = 2

x = 2

∴ The coordinates of P = P(0, _) = P(0, <u>2</u>)

Similarly, when x = 0, we get;

4·x + 2·y = 8

At the point x = 0;

4 × 0 + 2·y = 8

y = 8/2 = 4

y = 4

∴ The coordinates of Q = Q(_, 0) = Q(<u>4</u>, 0)

b) Rewriting the given equation in terms of 'y' gives;

y = (8 - 4·x)/2 = 4 - 2·x

y = 4 - 2·x

With the help of MS Excel, the points P and Q are plotted in the attached graph

c) The line of the graph of the function 4·x + 2·y = 8 for values of x from -2 to 3 can be added by Changing the Chart Type to 'Scatter with Smooth Lines and Markers' within MS Excel as presented in the included graph of the line.

3 0
3 years ago
I need details please
m_a_m_a [10]
Ok, first you need to read a - g and mark down the information you know. Also, this continuous function can look pretty much like anything long as it has the a - g constraints/rule. 

A) We know the domain(x values) is between -10 to infinity
(-10,-9,-8,-7,-6,-5,-4,-3-,2,-1,0,1,2,3,4,5,6,7,8,9,10, to ---------> infinity)
B) We know the range(y values) is between -6 to infinity
(-6,-5,-4,-3-,2,-1,01,2,3,4,5,6,7,8,9,10, to ---------> infinity) 

C) Next we know f(0) = f(4) = 0
So we know when x = 0  that f(0) = 0 or we can say  y = 0. We also know when f(4) = 0 so when x = 4 y = 0. So we have two points (0,0) and (4,0) that our function will be on so plot the two points (0,0) (4,0)

D) It tells us that f(x) (y) is increasing between the x values (-10,-6)  or (-2,2) or (4, to infinity)

E) It tells us that f(x) (y) is decreasing between the x values (-6,-2) or between (2,4)

F) Tells us that f(x) (y) is greater than or equal to between the x values of [-8,-4] or between the x values [0, to infinity) so this lets us know our drawing is going to be above or equal to 0 when we are in the values [-8,-4] or [0, to infinity)

G) Tells us that f(x) (y) is less than 0 when the function / drawing is between the x values of (-10, -8) or (-4,0)  

The picture is what the function could look like. It can be different but needs to following the rules that are given 




3 0
3 years ago
Given that (4,-8) is on the graph of f(x), find the corresponding point for the function f(x+3)
Murljashka [212]
The originial function is f (x).
 The original function contains the point (4, -8).
 The transformation f (x + 3) moves the graph 3 units to the left.
 Therefore, the new point is:
 (4 + 3, -8) = (7, -8)
 Answer:
 
The corresponding point for the function f (x + 3) is:
 (7, -8)
4 0
3 years ago
Multiply. Write your answer in simplest form.<br><br> 2 1/2 x 3 2/3
oksian1 [2.3K]
2 \frac{1}{2}  *  3 \frac{2}{3}  =   \frac{5}{2}  *   \frac{11}{3}
                    =  \frac{55}{6}
                    =  9 \frac{1}{6}

7 0
4 years ago
Read 2 more answers
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