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Vlad [161]
3 years ago
13

Write an equation of the line that is parallel to the line whose equation is 3y+ 7 = 2x and passes through the point (2;6).

Mathematics
1 answer:
Semmy [17]3 years ago
8 0

y=2/3x+14/3 this is because math is nath

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1/4 = x/12 solve for x
Vedmedyk [2.9K]
Answer: x=3
First you cross multiply
Next you swap sides then divide both sides by 4
6 0
3 years ago
Please help me, I think this is easy but I just don't get it...
Deffense [45]

Answer:

the last one?

Step-by-step explanation:

i dont know, but that one seems like it would

7 0
3 years ago
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Alissa cut a piece of string that was 17 feet long. Lydia cut a piece of string that was 5 yeards long. Alissa wanted to cut her
Ray Of Light [21]

Answer:

Ffff

Step-by-step explanation:

8 0
3 years ago
Divide 82 lbs 11 oz by 9
notsponge [240]
We need the equivalence 1 lbs = 16 oz
We convert the 82 lbs to oz using the equivalence, that is:
82(16) = 1312
therefore 82 lbs are equivalent to 1312 oz, so the total of ounces we have is:
1312 + 11 = 1323
and that is the figure we have to divide by 9
1323/9 = 147
that is 147 oz
we can convert to lbs by dividing by 16
147/16 = 9.19
therefore the result is 147 oz or 9.19 lbs
5 0
3 years ago
Consider an experiment in which a fair coin is tossed until a head is obtained for the first time. If this experiment is perform
pychu [463]

Answer:

P(A_1 = A_2 =A_3) = \frac{1}{1-\frac{1}{8}} -1 =\frac{1}{7}

Step-by-step explanation:

For this case we assume that the probability of obtain a head is 1/2

P(H) =\frac{1}{2}

We are conducting the experiment 3 times. And we want the probability that exactly the same number of tosses will be required for each of the 3 performances.

We can model the situation like this. Let A_i the number of tosses used in the performance, for this case A_i \geq 1

And the distribution for A_i would be a negative binomial with the following mass function:

P(A_i = r)= (1-\frac{1}{2})^{r-1} \frac{1}{2}= (\frac{1}{2})^r

Now we need to assume that the 3 performaces are independent from each other and we want this:

P(A_1 = A_2 =A_3) =\sum_{r=1} P(A_i = r)^3

And we can since we have the mass function we can replace:

P(A_1 = A_2 =A_3) =\sum_{r=1} (\frac{1}{2})^{3r}

P(A_1 = A_2 =A_3) = \sum_{r=1} (\frac{1}{8})^r

And as we can see we have a geamotric series and we can find the probability like this:

P(A_1 = A_2 =A_3) = \frac{1}{1-\frac{1}{8}} -1 =\frac{1}{7}

8 0
3 years ago
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