5 sin theta is equal to 3 then find the then find the value of 2 cos theta + 3 sin theta upon 3 sin theta + 4 cos theta
1 answer:
GIVEN:
5sinΦ = 3
so, sinΦ = 3/5
let p = 3 and h = 5 as sinΦ = p/h.
ANSWER:
So, by pythagorean theorem,
- b² = (5)² - (3)²
- b² = 25 - 6
- b = √16 = 4.
So, cosΦ = b/h = 4/5.
Now, 2cosΦ + 3sinΦ/3sinΦ + 4cosΦ
- 2 × 4/5 + 3 × 3/5 ÷ 3 × 3/5 + 4 × 4/5
- 8/5 + 9/5 ÷ 9/5 + 16/5
- 17/5 ÷ 25/5
- 17/5 × 5
- 17.
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