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tensa zangetsu [6.8K]
3 years ago
5

A) 2(5x – 3) = 24 b) 5(2x + 1) = 50

Mathematics
1 answer:
nadezda [96]3 years ago
8 0

Answer:

a) x=3

b) x=4.5

Step-by-step explanation:

2(5x – 3) = 24

10x-6=24

10x=30

x=3

5(2x + 1) = 50

10x+5=50

10x=45

x=4.5

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Whitepunk [10]

Answer:

Yes, she can.

Step-by-step explanation:

We have to find the surface area of the footrest and see if it greater than or less than 1 square yard.

The surface area of a rectangular prism is given as:

A=2(wl+hl+hw)

where w = width, l = length, h = height

The footrest is 15 inches by 7 inches by 9 inches. Its surface area is:

A = 2[(7 * 15) + (9 * 15) + (9 * 7)]

A = 2[105 + 135 + 63]

A = 2 * 303 = 606 square inches

1 square inch = 0.000771605 square yards

=> 606 square inches = 606 * 0.000771605 = 0.468 square yards

Since the surface area of the prism is less than 1 square yard, she can completely cover the footrest with the fabric.

4 0
3 years ago
An old bone contains 80% of its original carbon-14. Use the half-life model to find the age of the bone. Find an equation equiva
Ira Lisetskai [31]

Answer:

An old bone contains 80% of its original carbon-14 in 1844.6479 years

Step-by-step explanation:

We know that

half life time of C-14 is 5730 years

so, h=5730

now, we can use formula

P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }

we can plug back h

and we get

P(t)=P_0(\frac{1}{2})^{\frac{t}{5730} }

An old bone contains 80% of its original carbon-14

so,

P(t)=0.80Po

we can plug it and then we solve for t

0.80P_0=P_0(\frac{1}{2})^{\frac{t}{5730} }

0.80=(\frac{1}{2})^{\frac{t}{5730} }

\ln \left(0.8\right)=\ln \left(\left(\frac{1}{2}\right)^{\frac{t}{5730}}\right)

t=-\frac{5730\ln \left(0.8\right)}{\ln \left(2\right)}

t=1844.6479

So,

An old bone contains 80% of its original carbon-14 in 1844.6479 years


4 0
3 years ago
Read 2 more answers
Please someone help I need this done quick
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Step-by-step explanation:

f(x) = x² - 2x - 3

g(x) = 4x²

f(g(x)) = f(4x²)

f(4x²) = (4x²)² - 2(4x²) - 3

= 16x⁴ - 8x² - 3

6 0
3 years ago
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Answer:

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