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2 years ago

What is the total time it will take the snowball to melt completely

Mathematics

1 answer:

podryga [215]2 years ago

5 0

Point-slope form

y -24 = -4/5(x -0)

Find x when y is 0 (X-intercept)

0 -24 = -4/5(x -0)

-24 = -4/5x

x = -120/-4

x = 30

Answer: A. 30 minutes

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Solve for x. 5x - 1 = 26 x = 27/5 x = 5 x = -5

yan [13]

5x = 26 + 1
5x = 27
x = 27/5

Answer: A) or the first option ✅

4 0

3 years ago

Julissa is thinking about getting her Master’s degree. She will give up making $28,000 a year for the 2 years it takes to comple

beks73 [17]

Answer:

1.5 years

Step-by-step explanation:

She will give up making $28,000 per year for 2 years. This means that she will give up making $56,000 in total.

$28,000 × 2 = $56,000

She also pay $34,000 in total to costs to get her degree. She invested a total of $90,000.

$56,000 + $34,000 = $90,000

After graduating, she makes $60,000 a year. It will take her 1.5 years to recover her investment.

90,000/60,000 = 1.5

7 0

2 years ago

A building is 2ft from a 7 ft fence that surrounds the property. A worker wants to wash a window in the building 11ft from the g

777dan777 [17]

Answer:

Step-by-step explanation:

plug the numbers into the Pythagorean theorem

which is A^2 + B^2 = C^2

4 0

2 years ago

Read 2 more answers

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

X^2+25 A.(x+5)(x+5) B.(x+5)(x-5) C.(x-5)(x/5) D.prime

adell [148]

It’s prime because none of the other answers work.

8 0

2 years ago