Answer:
6.3 C
Explanation:
From the question,
Energy lost by the capacitor(half it stored energy) = 1/4CV².......................... Equation 1
Where C = Capacitance of the capacitor, V = Volatge across the parallel plate of the capacitor.
E = 1/4CV²
Given: C = 2.1 F, V = 6.0 V
Substitute these values into equation 1
E = 1/4(2.1)(6²)
E = 18.9 J
But,
E = 1/2QV..................... Equation 2
Where Q = amount of charge lost
Make Q the subject of the equation
Q = 2E/V................. Equation 3
Give: E = 18.9 J, V = 6.0 V
Q = 2(18.9)/6
Q = 6.3 C.
Use pythagorean theorem and inverse tangent.
a) magnitude - 29.15; angle - 59 degrees
b) magnitude - 234.09; angle - 110 degrees
c) magnitude - 0.4; angle - south
d) magnitude - 234.3; angle - 309.81 degrees
e) magnitude - 42.43; angle - 315 degrees
There is an easy and convenient technique to solve vectors without drawing them. With you scientific calculator, make sure that you are in mode CMPLX. In this case, the two vectors should sum up to the resultant vector. Since we are given with the resultant vector, let's just use subtraction. Input this into your calculator:
96.3∠75.2° - 56.4∠232°
The answer would be 59.32+137.55i. Convert this to the r∠θ format. The final answer would be 149.8∠66.67°. Therefore, the second displacement is 149.8 cm and makes an angle of 66.67° with the +x axis.
Answer:
The amount of water it displaces (shaded area ) weighs as much as the ship. The weight of the ship pulling down and the upthrust pushing up are equal and opposite forcers so the ship floats.
Explanation:
Now the weight of the ship is more than the maximum possible upthrust so it sinks to the buttom
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