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tamaranim1 [39]
3 years ago
9

An object starts from rest and accelerates at a rate of 3.0 m/s/s for 6.0 seconds. The velocity at the end of the 6.0 seconds is

Physics
1 answer:
Zepler [3.9K]3 years ago
6 0
Vf=vi+at
=0+3×6
=18m/s

the answer is D.
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A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that incre
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Complete Question

A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 1.60 T in 0.99 s. What is the resulting induced current if the loop has a resistance of 1.20  \ \Omega

Answer:

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Explanation:

From the question we are told that

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   The magnetic field at t_1 = 0.99 \ seconds is  B_f  = 1.60 \ T

     The resistance is  R = 1.20  \ \Omega

Generally the induced emf is mathematically represented as

      \epsilon  =  A * \frac{B_f - B_i }{ t_f - t_o }

=>   \epsilon  =  8.0 *10^{-4} * \frac{1.60  - 0.500 }{ 0.99- 0  }

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