An object starts from rest and accelerates at a rate of 3.0 m/s/s for 6.0 seconds. The velocity at the end of the 6.0 seconds is
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Length of the pipe = 0.39 m
Number of harmonics = 3
Now there are 3 loops so here we can say
now here at the center of the pipe it will form Node
we need to find the distance of nearest antinode
So distance between node and its nearest antinode will be
So the distance will be 6.5 cm