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3 years ago

The discoverer of radioactivity was

2 answers:

8 0

The dicoverer of radioactivity was in 1896 henri Becquerel was using naturally flurorescent minerals to study been discover in 1895 bu Wilhelm Roentgen.

Vikentia [17]3 years ago

5 0

Answer:

Henri Becquerel

Explanation:

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Are eggs a element, a compound, or a mixture

enyata [817]

Answer:

I'm gonna go with compund

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3 years ago

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Two parallel-plate capacitors have the same dimensions, but the space between the plates is filled with air in capacitor 1 and w

Aleks [24]

Explanation:

The capacitance in two parallel-plate capacitors is:

$C=\frac{K\epsilon_oA}{d}$

For air, we have $K_1=1$

For plastic, we have $K_2=2.25$

Hence:

$C_1=\frac{K_1\epsilon_oA}{d_1}=\frac{\epsilon_oA}{d_1}\\C_2=\frac{K_2\epsilon_oA}{d_2}=2.25(\frac{\epsilon_oA}{d_2})$

a) Recall that the potential difference between the plates is the same ( $V_1=V_2=V$ ). The electric field is given by:

$E_1=\frac{V_1}{d_1}=\frac{V}{d_1}\\E_2=\frac{V_2}{d_2}=\frac{V}{d_1}$

The potential difference is defined as:

$V_1=\frac{Q_1}{C_1}=V\\V_2=\frac{Q_2}{C_2}=V$

Replacing:

$E_1=\frac{Q_1}{C_1d_1}\\E_2=\frac{Q_1}{C_1d_2}\\\\E_1d_1=\frac{Q_1}{C_1}\\E_2d_2=\frac{Q_1}{C_1}\\E_1d_1=E_2d_2\\\frac{E_1}{E_2}=\frac{d_2}{d_1}$

b) The energy is defined as:

$U=\frac{1}{2}CV^2$

So:

$U_1=\frac{1}{2}C_1V_1^2=\frac{1}{2}C_1V^2\\U_2=\frac{1}{2}C_2V_2^2=\frac{1}{2}C_2V^2\\U_1=\frac{1}{2}\frac{\epsilon_oA}{d_1}V^2\\U_2=\frac{1}{2}\frac{2.25\epsilon_oA}{d_2}V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=V^2\\\frac{2U_1d_1}{\epsilon_oA}=V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=\frac{2U_1d_1}{\epsilon_oA}\\\frac{U_1}{U_2}=0.44\frac{d_2}{d_1}$

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3 years ago

A 1,600 kg car is traveling with a speed of 20 m/s. Find the net force that is required to bring the car to a halt in a distance

Pie

256N. I love physics so.... yerp

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4 years ago

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Two objects charged with an equal amount of charge interact with each other with a force

pav-90 [236]

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3 years ago

Which symbol represents a type of electromagnetic radiation released during radioactive decay?

Lena [83]

The correct option is (D) Gamma ( $_0^0\gamma$ )

Explanation:
Now this question is a tricky one because all of these options are somehow involved in radioactive decay; however, in this case the SYMBOL is required NOT the elements. There are three symbols involved in radioactive decay, which are:
1. α for alpha decay
2. β for beta decay
3. γ for gamma decay

In the options only one symbol is present which is gamma. Hence option (D) Gamma ( $_0^0\gamma$ ) is the correct answer.

-i

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4 years ago