Answer:
The area of the base of the pyramid is 109.2 mm.
Step-by-step explanation:
The area of the base of a hexagonal pyramid is given by the area of a hexagon:
Where:
P: is the perimeter
a: is the apothem
We need to find the perimeter and the apothem.
The perimeter is equal to:
Where:
s: is the side of the pyramid
And the apothem is:
So, to calculate the apothem and the perimeter we need to calculate the side of the pyramid. We can find it from the volume of the pyramid:
Where:
h: is the height = 4 mm
V: is the volume = 144 mm³
Then, the side is:
Now, we can find the perimeter and the apothem.
Finally, the area is:
Therefore, the area of the base of the pyramid is around 109 mm.
I hope it helps you!
Answer:
y=2x-5
Step-by-step explanation:
Consecutive even integers are 2 apart
they are x and x+2
sum means add
so
they add to 234 so
x+x+2=234
2x+2=234
minus 2 from both sides
2x=232
divide both sides by 2
x=116
x+2=118
the numbers are 116 and 118 and the larger one is 118
Equation of the line:
y=mx+b
Ordinate at the origin (where the line cut the y-axis): b=1
B=(-5,5)=(xb,yb)→xb=-5, yb=5
C=(0,1)=(xc,yc)→xc=0, yc=1
m=(yc-yb)/(xc-xb)
m=(1-5)/(0-(-5))
m=(-4)/(0+5)
m=(-4)/(5)
m=-(4/5)
y=mx+b
y=-(4/5)x+1
Multiplying the equation by 5:
5[y=-(4/5)x+1]
5y=-4x+5
Adding 4x both sides of the equation:
5y+4x=-4x+5+4x
4x+5y=5
Answer: The equation for BC is: Third option 4x+5y=5