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Y_Kistochka [10]
3 years ago
6

What is 4x^2-1/ (x+4) (2x-1) simplified

Mathematics
2 answers:
pentagon [3]3 years ago
7 0

Answer:

i don't know

Step-by-step explanation:

it is very hard

sorry !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Nadusha1986 [10]3 years ago
5 0

Answer:

:)

Step-by-step explanation:

\frac{4x^2 - 1}{(x+4)(2x-1)} = \frac{(2x)^2 - (1)^2}{(x+4)(2x-1)}

                 =\frac{(2x-1)(2x+1)}{(x+4)(2x-1)}\\\\=\frac{2x+1}{x+4}

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Write the equation of a circle with a center at (-1,2) and a radius of 7
Sever21 [200]

Answer:

(x+1)^2+(y-2)^2=49

Step-by-step explanation:

The standard form for the equation of a circle is (x-h)^2+(y-k)^2=r^2 where  r  is the radius, and the center is (h, k).

(h, k) = (-1, 2),  r = 7

(x-(-1))^2+(y-2)^2=7^2\\\\(x+1)^2+(y-2)^2=49

5 0
3 years ago
How many hours and minutes elapsed from 8:00 a.m to 2:30 p.m?
seraphim [82]

Answer:

6 hours and 30 mins

Step-by-step explanation:

This is right answer because from 8:00 to 9:00 is 1 hour and each hour is 60 mins and each minute is 60 secs. I hope this helps and please give me the crown

6 0
3 years ago
What is the answer to -6(4r+2)+5
RideAnS [48]

Answer:

-24r - 7

Step-by-step explanation:

-6(4r + 2) + 5

-24r - 12 + 5

-24r - 7

Best of Luck!

5 0
3 years ago
Which of the following is not a proportion 1/4=3/12 4/10=12/20 2/4=3/6 8/6=20/15
Lera25 [3.4K]
The answer is 4/10 = 12/20.
6 0
4 years ago
Read 2 more answers
Assume that the population proportion is 0.46. Compute the standard error of the proportion, σp, for sample sizes of 500,000; 1,
sladkih [1.3K]

Answer:

a) 0.00070

b) 0.00050

c) 0.00022

d) 0.00016

e) 0.00005

Step-by-step explanation:

Standard error for proportion formula

S.E = √P(1 - P)/n

Where P = proportion

n = number of samples

Assume that the population proportion is 0.46. Compute the standard error of the proportion, σp, for sample sizes of a) 500,000

S.E = √P(1 - P)/n

= √0.46 × 0.54/500000

= √ 4.968 ×10^-7

= 0.0007048404

≈ 0.00070

b) 1,000,000

√P(1 - P)/n

= √0.46 × 0.54/1000000

= 0.0004983974

≈ 0.00050

c) 5,000,000

√P(1 - P)/n

= √0.46 × 0.54/5000000

= √ 4.968 ×10^-8

= 0.0002228901

≈ 0.00022

d) 10,000,000

√P(1 - P)/n

= √0.46 × 0.54/10000000

= √2.484 ×10^-8

= 0.0001576071

≈ 0.00016

e) 100,000,000

√P(1 - P)/n

= √0.46 × 0.54/100000000

= √2.484 × 10^-9

= 0.0000498397

= 0.00005

4 0
3 years ago
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