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Romashka-Z-Leto [24]

3 years ago

15

Which expressions will help you find the areas of the rectangular faces? Select all that apply.

1 answer:

ratelena [41]3 years ago

6 0

8x12 i am asssuming that that’d what it is

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Suppose you have a random variable that is uniformly distributed between 1 and 29. what is the expected value for this random va

Kryger [21]

Assuming the distribution is continuous, you have

$\mathbb E(X)=\displaystyle\int_1^{29}\frac x{29-1}\,\mathrm dx=\dfrac1{28}\int_1^{29}x\,\mathrm dx=15$

If instead the distribution is discrete, the value will depend on how the interval of number between 1 and 29 are chosen - are they integers? evenly spaced rationals? etc

3 0

3 years ago

Find the perimeter.<br> Perimeter = [?]<br> Simplify your answer completely.

viktelen [127]

The answer would be 119 and 4/7

3 0

2 years ago

Read 2 more answers

Please show your work

Paladinen [302]

Answer:

see in the picture, the perimeter of this rectangle is

2( x + 3x) = 8x but the perimeter is 65.6

=> 8x = 65.6

<=> x = 65.6/8

=> x = 8.2

7 0

3 years ago

Use the zero product property to find the solutions to the equation x2 + x – 30 = 12.

Butoxors [25]

Answer:

x= 6, -7

Step-by-step explanation:

3 0

2 years ago

A university is building a new student center that is two- thirds the distance from the arts center to the residential complex.

Natasha2012 [34]

Answer:

$C = (\frac{21}{5},\frac{33}{5})$

Step-by-step explanation:

Given

Points: (1, 9) and (9, 3)

Ratio = 2/3

Required

Determine the coordinate of the center

Represent the ratio as ratio

$Ratio = 2:3$

The new coordinate can be calculated using

$C = (\frac{mx_2 + nx_1}{n + m},\frac{my_2 + ny_1}{n + m})$

Where

$(x_1,y_1) = (1, 9)$

$(x_2, y_2) = (9, 3)$

$m:n = 2:3$

Substitute these values in the equation above

$C = (\frac{2 * 9 + 3 * 1}{3 + 2},\frac{2 * 3 + 3 * 9}{2 + 3})$

$C = (\frac{18 + 3}{5},\frac{6 + 27}{5})$

$C = (\frac{21}{5},\frac{33}{5})$

Hence;

<em>The coordinates of the new center is </em> $C = (\frac{21}{5},\frac{33}{5})$ <em></em>

7 0

3 years ago