All categories

3 years ago

How many hours and minutes elapsed from 8:00 a.m to 2:30 p.m?

Mathematics

1 answer:

seraphim [82]3 years ago

6 0

Answer:

6 hours and 30 mins

Step-by-step explanation:

This is right answer because from 8:00 to 9:00 is 1 hour and each hour is 60 mins and each minute is 60 secs. I hope this helps and please give me the crown

You might be interested in

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

postnew [5]

Given that the vertex of the parabola is (4,-3)

The parabola passes through the point (2,-1)

We need to determine the standard form of the equation of the parabola.

<u>Standard form of the equation of the parabola:</u>

The standard form of the equation is $y=a(x-h)^2+k$ where the vertex is (h,k) and a is the constant.

Substituting the vertex (4,-3) in the above equation, we get;

$y=a(x-4)^2-3$ ---------------(1)

Substituting the point (2,-1) in the above equation, we have;

$-1=a(2-4)^2-3$

$-1=a(-2)^2-3$

$-1=4a-3$

$2=4a$

$\frac{1}{2}=a$

Thus, the value of a is $\frac{1}{2}$

Substituting the value of a in the equation (1), we get;

$y=\frac{1}{2}(x-4)^2-3$

Thus, the standard form of the equation of the parabola is $y=\frac{1}{2}(x-4)^2-3$

3 0

3 years ago

The number 3456 is divisible by which single-digit numbers?

nata0808 [166]

Answer:

1, 2, 3, 4, 6, 8, 9

4 0

4 years ago

The angle of parallelogram is 12 less than 5 times the measure of these angle

Y_Kistochka [10]

let one angle be X

so, other angle be 5x-12

ATQ

X+5x-12=180

6x=180-12

6x=168

X=168/6

hence X=28

now,one angle=28

other angle is 5×28-12

= 140-12.

= 128

5 0

3 years ago

3/4 c - 7/12 + 7/24 c + 2/3 - 1/6 c

CaHeK987 [17]

Answer:

c+1/12

Step-by-step explanation:

18/24c-7/12+7/24c+8/12-4/24c=c+1/12

8 0

3 years ago

Read 2 more answers

Will award brainest, being timed, help ASAP

zhenek [66]

Well it's hard to visually inspect this long text; let's look at it.

$\begin{matrix} \textrm{Secs} & \textrm{GroupR} & \textrm{GroupS} \\ 45 & 1 & 0 \\ 50 & 2 & 1 \\ 55 & 1 & 1 \\ 60 & 2 & 2 \\ 65 & 1 & 0\\ 70 & 1 & 2 \\ 75 & 1 & 0 \\ 80 & 1 & 1 \\ 85 & 1 & 0 \\ 90 & 2 & 2 \\ 95 & 1 & 1 \\ 100 & 2 & 1 \\ 105 & 1 & 1 \\ 110 & 2 & 2 \\ 115 & 1 & 1 \\ 120 & 2 & 1 \\ \end{matrix}$

Based on visual inspection the averages look about the same.

7 0

4 years ago

Read 2 more answers