Answer:
No
Step-by-step explanation:
A linear equation is an equation of a straight line, which means that the degree of a linear equation must be
0 or 1 for each of its variables. In this case, the degree of variable y is 1
and the degree of variable x is 2.
Not Linear
Only two real numbers satisfy x² = 23, so A is the set {-√23, √23}. B is the set of all non-negative real numbers. Then you can write the intersection in various ways, like
(i) A ∩ B = {√23} = {x ∈ R | x = √23} = {x ∈ R | x² = 23 and x > 0}
√23 is positive and so is already contained in B, so the union with A adds -√23 to the set B. Then
(ii) A U B = {-√23} U B = {x ∈ R | (x² = 23 and x < 0) or x ≥ 0}
A - B is the complement of B in A; that is, all elements of A not belonging to B. This means we remove √23 from A, so that
(iii) A - B = {-√23} = {x ∈ R | x² = 23 and x < 0}
I'm not entirely sure what you mean by "for µ = R" - possibly µ is used to mean "universal set"? If so, then
(iv.a) Aᶜ = {x ∈ R | x² ≠ 23} and Bᶜ = {x ∈ R | x < 0}.
N is a subset of B, so
(iv.b) N - B = N = {1, 2, 3, ...}
Since it is not perfectly straight it’s not linear so
*nonlinear association
The line goes down not up so it’s
*negative association
If your teacher wants to count the point outside of the regular line it would be no association
The two that most fit this graph are nonlinear and negative association
Answer:
B
Step-by-step explanation:
I don't know it kinda makes sense.
Answer:
Bart’s bikes ll .50
Step-by-step explanation:
