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ExtremeBDS [4]
3 years ago
11

What is 6=x over 8 for fractions

Mathematics
2 answers:
boyakko [2]3 years ago
6 0

Answer:

48

<h3><em><u>Could I please have BRAINLIEST.</u></em></h3>
9966 [12]3 years ago
4 0

Answer:

x = \frac{3}{4}

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Find a tangent vector of unit length at the point with the given value of the parameter t. r(t) = 2 sin(t)i + 7 cos(t)j t = π/6
alina1380 [7]

The tangent vector to r(<em>t</em>) at any <em>t</em> in the domain is

\mathbf T(t)=\dfrac{\mathrm d\mathbf r(t)}{\mathrm dt}=2\cos t\,\mathbf i-7\sin t\,\mathbf j

At <em>t</em> = π/6, the tanget vector is

\mathbf T\left(\dfrac\pi6\right)=\sqrt3\,\mathbf i-\dfrac72\,\mathbf j

To get the unit tangent, normalize this vector by dividing it by its magnitude:

\left\|\mathbf T\left(\dfrac\pi6\right)\right\|=\sqrt{(\sqrt3)^2+\left(-\dfrac72\right)^2}=\dfrac{\sqrt{61}}2

So the unit tangent at the given point is

\dfrac{\mathbf T\left(\frac\pi6\right)}{\left\|\mathbf T\left(\frac\pi6\right)\right\|}=2\sqrt{\dfrac3{61}}\,\mathbf i-\dfrac7{\sqrt{61}}\,\mathbf j

4 0
3 years ago
Jamel wants to buy a PS 5. He found it for $500
Musya8 [376]

Answer:

150

Step-by-step explanation:

its 150 without taxes

7 0
2 years ago
Solve: 3/x-4 &gt;0 A.x -4 C.x&gt;4 D.x&lt;-4
rosijanka [135]

Answer:

C. x>4

Step-by-step explanation:

3/(x-4) > 0

3>0, so

x-4 >0

x > 4

4 0
3 years ago
(c) Do we need both rates? In real life, when will each rate become useful?
abruzzese [7]
What do you mean by “rates” ?
6 0
3 years ago
Gizmo can eat 2 bowls of kibbles in 3 minutes. Leo can eat one bowl of kibbles in 6 minutes. Together, how many bowls of kibbles
Westkost [7]
Gizmo eats two bowls in 3 minutes, which means in a minute he would eat a fraction of 2/3 of the bowl.
On the other hand, leo eats one bowl in 6 minutes hence in a minute he eats a fraction of 1/6 of a bowl. 
When both combine, then in one minute they can eat a fraction of 2/3+1/6= 5/6.
Therefore, in ten minutes they will take 10× 5/6 = 8.333 equivalent to 8 bowls and a third of a bowl
4 0
2 years ago
Read 2 more answers
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