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elena55 [62]
3 years ago
11

Which is an equation of the line that passes

Mathematics
1 answer:
yan [13]3 years ago
3 0

Answer:

y=1/2x+6

Step-by-step explanation:

Lines that are parallel will have the same slope, so the slope will remain 1/2. However, the y-intercepts can't be the same because then they will overlap each other instead. So we must solve for the missing y-intercept in this case:

y = 1/2x + b

4 = 1/2(-4) + b

4 = -2 + b

6 = b

b = 6

Since the y-intercept is b=6, then the equation of the line that passes through the point (-4,4) and is parallel to the line y=1/2x-4 is y=1/2x+6

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Which graph shows that Cindy reads about of the time while riding in the car?
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Answer:

The 2nd

Step-by-step explanation:

It shows the denominator of 3/4

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4 years ago
Will give brainliest
pychu [463]

The equation of a hyperbola is  x^{2}/9 - y^{2}/4 = 1

What are the steps to Hyperbola equation ?

To find the equation of hyperbola, the following steps must be taken. You need to identify;

  • The coordinate of the center
  • The coordinate of the vertices
  • The coordinate of the foci

The general equation of a hyperbola can be expressed as

x^{2}/a^{2} - y^{2}/b^{2} = 1

From the graph, we have the following parameters

a = 3

a^{2} = 3^{2} = 9

b = 2

b^{2} = 2^{2} = 4

The equation of a hyperbola can be expressed as

x^{2}/9 - y^{2}/4 = 1

The vertices = V(+/-a,0) = (+/-3,0)

The center = C(0,0)

The focus = F(+/-C, 0)

Where C^{2} = a^{2}  + b^{2}

C = \sqrt{9 + 4}

C = \sqrt{13}

Focus = F(+/- \sqrt{13}, 0)

The general equation for asymptote = +/- b/a X

= +/-2/3X

Therefore, the equation of a hyperbola can be expressed as

x^{2}/9 - y^{2}/4 = 1

Learn more about hyperbola here: brainly.com/question/3405939

#SPJ1

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2 years ago
A is an unknown number when you round a to the nearest thousand you get 21,000 when you round a to the nearest hundred you get 2
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The unknown number a should be 20,500.

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on monday, steven read 9 pages of his new book. to finish the first chaper on tuesday, he needs to read double the numbe of page
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