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Murljashka [212]
3 years ago
7

Three playing cards are placed in a row, from left to right. Each card is of a

Mathematics
1 answer:
qaws [65]3 years ago
8 0

Answer:

hifgreeg33ctvtvunu

Step-by-step explanation:

highhb tug 5h6g6g5g5g

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vagabundo [1.1K]
The answer is number 4
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3 years ago
Find mABC<br><br> A-54<br> B-135<br> C-15<br> D-126
bagirrra123 [75]
It’s B



Glad I could help
7 0
3 years ago
An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
In the diagram below, PQ and RS are parallel. Based on the angle measures in the diagram, what is the value of X?
Butoxors [25]

Answer:

x would be equal to 70 grades

Step-by-step explanation:

The angle QRS is equal to 180 - 130 = 50 grades.

We add up that with the other 60 grades on the left, and we encounter ourselves with a simple equation:

60 + x + 50 = 180

x = 70

Hope this was helpful

4 0
3 years ago
Determine if there is a proportional relationship between the two quantities
Shalnov [3]

Answer:

The table a not represent a proportional relationship between the two quantities

The table b represent a proportional relationship between the two quantities

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

<u><em>Verify each table</em></u>

<em>Table a</em>

Let

A ----> the independent variable or input value

B ----> the dependent variable or output value

the value of k will be

k=\frac{B}{A}

For A=35, B=92 ---> k=\frac{92}{35}=2.63

For A=23, B=80 ---> k=\frac{80}{23}=3.48

the values of k are different

therefore

There is no proportional relationship between the two quantities

<em>Table b</em>

Let

C ----> the independent variable or input value

D ----> the dependent variable or output value

the value of k will be

k=\frac{D}{C}

For C=20, D=8 ---> k=\frac{8}{20}=0.40

For C=12.5, D=5 ---> k=\frac{5}{12.5}=0.40

the values of k are equal

therefore

There is a proportional relationship between the two quantities

The linear equation is equal to

D=0.40C

7 0
3 years ago
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