Answers:
k = 13The smallest zero or root is x = -10
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Work Shown:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
As this is probability, we can use the next formulas and tell how is this going to be:
P(A) = student on the dean's list
<span>P(B) = student taking calculus </span>
<span>P(A n B) = 0.042 </span>
<span>P(A) = 0.21 </span>
<span>So, P(B) = 0.042/0.21 </span>
<span>= 0.2
So the probability here is of 0.2</span>
Value of x is 35°
Step-by-step explanation:
- Step 1: Since the line segment is a perpendicular bisector, the angle formed is equal to 90° and two triangles are also formed.
Find x using the property of triangles that sum of angles of a triangle is 180°
⇒ x° + 55° + 90° = 180°
⇒ x° + 145° = 180°
∴ x = 180 - 145 = 35°
Answer:
8/7
Step-by-step explanation:
0.8/0.7=8/7
Answer:
12.78 units
Step-by-step explanation:
The formula for arc length =
2πr × θ/360
From the question:
θ = 122°
r = 6 units
Therefore, the arc length =
2 × π × 6 × (122/360)
= 12.775810125 units
Approximately to the nearest hundredth = 12.78 units
Therefore, the length of arc CE is 12.78 units