She earns 32.40 for working 4 hrs.....32.40/4 = 8.10 per hr
y = 8.10h...where y is the amount of money earned and h is the number of hrs worked
F(x) = 20x+300
you sub in the x values (120 hours and 100 hours) for each equation
the only one they both work for is the last one
f(x) = 20x + 300
f(100) = (20 * 100) + 300 = 2000 + 300 = 2300
f(120) = (20 * 120) + 300 = 2400 + 300 = 2700
Answer:
- Considering the temperature is 0°C and
- It is changing at a rate of -3 per hour.
So, it took 11 hours for the change in temperature to be -33.
Step-by-step explanation:
Rate of change basically means the amount of change to how long it takes for the change to occur.
Rate of change = Change in Value/ Change in time
On a certain day the temperature changed at a rate of -3 per hour.
Let suppose the Temperature at 8:00 = 0°C
As the temperature changed at a rate of -3 per hour.
It means the Temperature at 9:00 = -3°C.
so
Rate of change = (-3 - 0)/(9:00 - 8:00) = -3°C per hour
So, the temperature to be -33°C, it would take 11 hour as -3 × 11 = -33.
Therefore, it took 11 hours for the change in temperature to be -33.
Answer:
See below
Step-by-step explanation:
y = -6x^2 + 24x-100
solve for 'x'
y + 100 = -6x^2 + 24x = -6(x^2-4x) complete the square for x
(y+100) /(-6 ) = (x-2)^2 -4 add 4 to both sides
(y+100)/(-6) +4 = (x-2)^2 sqrt both sides
sqrt [ ( y+100)/(-6) + 4 ] + 2 = x change x and y
y = ± sqrt [ (x+100)/(-6) + 4 ] + 2 simplify (if needed)
<u>y = ± sqrt( -x/6 -12.666) + 2 </u>
