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2 years ago

Jackson eats 3/4 cup of food in the morning and 3/4 cup of food at night. How many cups of food does Jackson eat in 5 days

Mathematics

2 answers:

vladimir2022 [97]2 years ago

6 0

Well since someone already answered this , i agree with them on the answer ! have a nice day !

Sonja [21]2 years ago

5 0

Answer:

Jackson eats 15/2 cups of food in 5 days.

Step-by-step explanation:

If Jackson eats 3/4 of food in the morning and at night then he eats 3/2 of food a day or 1.5 cups of food a day.

1.5*5 = 7.5

3/2*5=15/2

Hope this helps!!

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Solve this expression 5x^2-13x-6

torisob [31]

Answer:

x= -2/5 and x= 3

Step-by-step explanation:

Given equation is,

5x^2 - 13x - 6 = 0

Or, 5x^2 - 15x + 2x - 6 = 0 ( using middle term method)

Or, 5x( x- 3) + 2 (x-3) = 0

Or, (x-3) (5x+2) = 0

Now, x will have 2 answers because it's degree is 2. Total number of values depends on the power of variable.

So, x= 3 or, 5x = -2

Or, x= -2/5

So, the answer is x= -2/5 and x= 3.

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3 years ago

Misha measured a distance of 60 feet from her kitchen to the bedroom. What is the equivalent number of meters.

Nikitich [7]

1 feet = 0.3048 meters
So we do a unit conversion to cancel out the feet unit.
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3 years ago

If sin(t) = 3/5 and t is in the 2nd quadrant, find cos(t).

NemiM [27]

Cosine is $\frac{hypotenuse}{adjacent}$ .

Apply the equation:

$sin(t) = \frac{3}{5} \\3^2 + b^2 = 5^2\\b^2 = 5^2 - 3^2\\\\\sqrt{b^2} = \sqrt{5^2}- \sqrt{3^2}\\\\\\b = 5 - 3 \\\\b = 2$

B is the adjacent side so

cosine is:

Cos(t) = 5/2

Have a great day,

And I hope this helps you!

5 0

2 years ago

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SCORPION-xisa [38]

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4 0

2 years ago

Consider the following.3x + 3y = 8(a) Find y' by implicit differentiation.(b) Solve the equation explicitly for y and differenti

ludmilkaskok [199]

Answer:

a.y'=-1

b.y'=-1

c.Yes

Step-by-step explanation:

We are given that consider a function

$3x+3y=8$

Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable

Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.

a. $3x+3y=8$

Differentiate w.r.t x then we get

$3+3\frac{dy}{dx}=0$

$3\frac{dy}{dx}=-3$

$\frac{dy}[dx}=\frac{-3}{3}=-1$

$\frac{dy}{dx}=y'=-1$

b. $3x+3y=8$

$3y=8-3x$

$y=\frac{8-3x}{3}$

Differentiate w.r.t x then we get

$\frac{dy}{dx}=\frac{-3}{3}=-1$

$\frac{dy}{dx}=y'=-1$

When we substituting the value of y obtained from part b into a solution of part a then we get

$y'=-1$

Hence, solutions are consistent.

8 0

2 years ago