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mr_godi [17]
3 years ago
10

Which expression is equivalent to cos 120°?

Mathematics
1 answer:
ryzh [129]3 years ago
4 0

Answer:

cos 120° = -1/2

Step-by-step explanation:

cos 120° =  (adjacent side) / (hypotenuse.

Here the adjacent side (the side next to the central angle in this 30-60-90 triangle) is -1.  Then the hypotenuse is 2 and the opposite side is √3.

Thus, cos 120° = -1/2

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Please help me find domain/ range and equation
Ivanshal [37]

Answer:

The domain is the x axis from - 10 to 10 horizontal and the range is the y axis - 10 to 10 vertical

6 0
3 years ago
Read 2 more answers
Help please :c!
LUCKY_DIMON [66]

Answer:

see the procedure

Step-by-step explanation:

we know that

m∠1+m∠2=180° -----> supplementary angles (form a linear pair)

we have

m∠1=27° ----> given problem

substitute the measure of m∠1 in the equation above and solve for m∠2

27°+m∠2=180°

Subtract 27° both sides

27°+m∠2-27°=180°-27° ----> by subtraction property of equality

m∠2=153°

4 0
3 years ago
Need hello fast I don’t know what to do
Free_Kalibri [48]

35 + 14
The greatest common factor for both is 7. Factor out 7

7(5 + 2) is your answer

Hope this helps

8 0
4 years ago
Find the value of the x in the equation 4(6x-9. 5)=46.
Alborosie

Following are the calculation to<u> find the value of x</u>:

Given:

\to 4(6x-9. 5)=46\\

To find:

x=?

Solution:

\to 4(6x-9. 5)=46\\\\\to 24x- 38.0=46\\\\\to 24x =46-38\\\\\to 24x= 8\\\\\to x= \frac{8}{24}\\\\\to x= \frac{1}{3}\\\\

Therefore, the final answer is "\bold{\frac{1}{3}}".

Learn more:

brainly.com/question/4921853

6 0
3 years ago
In △ABC, point D∈AC
Maslowich
<h3>Answer:</h3>
  • ABDC = 6 in²
  • AABD = 8 in²
  • AABC = 14 in²
<h3>Explanation:</h3>

A diagram can be helpful.

When triangles have the same altitude, their areas are proportional to their base lengths.

The altitude from D to line BC is the same for triangles BDC and EDC. The base lengths of these triangles have the ratio ...

... BC : EC = (1+5) : 5 = 6 : 5

so ABDC will be 6/5 times AEDC.

... ABDC = (6/5)×(5 in²)

... ABDC = 6 in²

_____

The altitude from B to line AC is the same for triangles BDC and BDA, so their areas are proportional to their base lengths. That is ...

... AABD : ABDC = AD : DC = 4 : 3

so AABD will be 4/3 times ABDC.

... AABD = (4/3)×(6 in²)

... AABD = 8 in²

_____

Of course, AABC is the sum of the areas of the triangles that make it up:

... AABC = AABD + ABDC = 8 in² + 6 in²

... AABC = 14 in²

6 0
3 years ago
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