Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
Answer:
19.2 seconds
Step-by-step explanation:
1.2 times 8 which equals 9.6
9.6 times 2
Your answer will x= 5y/3-25/3
9514 1404 393
Answer:
B. (0, –2)
Step-by-step explanation:
Put the (x, y) values into the given formula.
(x, y) ⇒ (x +5, y -2)
B(-5, 0) ⇒ B'(-5+5, 0-2) = B'(0, -2)
