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Doss [256]
3 years ago
10

A BAG CONTAINS 10 RED BALLS AND FIVE BLUE BALLS WHAT IS TGE CHANCE OF PICKING A BLUE BALL.PLEASE EXPLAIN HOW TO SOLVE IT​

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
4 0

Answer:

5/15

Step-by-step explanation:

there are 15 balls altogether, 5 of which are blue meaning there is a 5/15 chance of picking a blue ball which as a percentage is 33.33% chance

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Alex needs to varnish the top And the bottom of a dozen rectangular wooden planks planks are 8 feet long and 3 feet wide each pi
meriva

Answer:

It will cost approximately $16.12 to varnish all the wooden planks.                                            

Step-by-step explanation:

We are given the following in the question:

Number of rectangular planks = 12

Dimension of the rectangular wooden plank:

Length = 8 feet

Width = 3 feet

Area covered by I bottle of varnish = 125 Square feet

Cost of 1 bottle of varnish = 3.50 units

Area of 1 rectangular plot =

A = \text{Length}\times \text{Width}\\A = 8\times 3\\A = 24\text{ square feet}

Total area to be covered by varnish =

= \text{Area of 1 plank}\times 12\times \text{Top area and bottom area}\\=24\times 12\times 2\\=576

Number of varnish bottles required =

n = \dfrac{\text{Total area}}{\text{Total area covered by 1 varnish bottle}} = \dfrac{576}{125} = 4.608

Cost of varnishing =

=\text{Cost of 1bottle of varnish}\times \text{Number of varnish bottles}\\=4.608\times 3.50\\=\$16.12

Thus, it will cost approximately $16.12 to varnish all the wooden planks.

6 0
3 years ago
Declmal answers
pogonyaev

Answer:

We can break this down:

The student has a one out of five chance of getting a correct answer, and a four out of five chance of an incorrect answer. We can express the students odds of getting one incorrect answer as 4/5. In order to get the odds of two wrong answers, we need to multiply this answer again by the odds of choosing a wrong answer. Therefore:

The odds of one wrong answer = 4/5

The odds of two wrong answers = (4/5) * (4/5) = 16/25 chance of getting both of the questions wrong.

Step-by-step explanation:

3 0
3 years ago
A ship is anchored off a long straight shoreline that runs north and south. From two observation points 16 miles apart on shore,
ELEN [110]
D - the shortest distance from the ship to the shore.
d / ( 17 - x ) = tan 32° = 0.62487
d / x = tan 53° = 1.32704
d = 0.62487 ( 17 - x )
d = 1.32704 x
0.62487 ( 17 - x ) = 1.32704 x
10.62279 - 0.62487 x = 1.32704 x
x = 10.62279 : 1.95191
x = 5.44226 miles
d = 5.44226 · 1.32704
Answer:
d = 7.222  miles
6 0
3 years ago
f the points (-4, 1) and (2, 1) are the endpoints of a diameter of a circle, where is the center? A) (-7, 1) B) (-1, 1) C) (1, -
Ulleksa [173]

Answer:

B

Step-by-step explanation:

The centre is at the midpoint of the endpoints of the diameter.

Using the midpoint formula, then

centre = ( \frac{-4+2}{2}, \frac{1+1}{2} ) = (- 1, 1 ) → B

4 0
3 years ago
If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
3 years ago
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