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Gnom [1K]
3 years ago
12

14x + 5y = -6 Slope intercept form

Mathematics
2 answers:
andrew11 [14]3 years ago
7 0

Answer:

y=-2.8x-1.2

Step-by-step explanation:

5y=-14x-6

y=-14/5x-6/5

y=-2.8x-1.2

Annette [7]3 years ago
7 0
The answer is : -14/5x -6/5

Explanation:
5y= -6-14x
y= -6/5 -14/5x

Standard form: -14/5x-6/5
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Which inequality is true for all real numbers? check all that apply.
skad [1K]

Answer:

<h2>3. If a ≥ b, then a + c ≥ b + c </h2><h2>4. If c > d, then a– c < a – d</h2>

Step-by-step explanation:

The inequalities 3 and 4 are the right ones, because they are actually properties of inequalities.

The other choices aren't correct. For example, the first choice: a – b < a + b, it's not true, because you must apply the same change at each side of the inequality, otherwise you'll ruin the expression.

Choices 2 and 5 are also false.

Therefore, the right answers are 3 and 4.

8 0
3 years ago
Read 2 more answers
A triangular prism has a volume of 2500 cubic feet. What is the length of the prism if its triangular bases are right triangles,
seraphim [82]

Answer:

25 ft

Step-by-step explanation:

V = AH, where A = area of the base, and H = height (length) of the prism

A = bh/2 for a triangle

V = bh/2 × H

2500 = (10)(20)/2 × H

2500 = 100H

H = 25

Answer: 25 ft

5 0
1 year ago
PLEASE HURRY
jek_recluse [69]
C is the answer i believe
5 0
3 years ago
Read 2 more answers
2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
3 years ago
Choose the triangle that seems to be congruent to the given one
vivado [14]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
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