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3 years ago

The greater of two consecutive integers is 20 more than twice the smaller. find the integers.

Mathematics

1 answer:

Kipish [7]3 years ago

7 0

Let x represent the smaller. Then x+1 is the greater of the two.

... x+1 = 2x +20

... 0 = x + 19 . . . . . subtract x+1

... x = -19

Your two integers are -19 and -18.

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2x³-8=0<br> How do I solve this problem ?

wlad13 [49]

Answer:

$x=2^{\frac{2}{3}}$

Step-by-step explanation:

1) Add 8 to both sides.

<em /> $2x^3=8$

2) Divide both sides by 2.

$x^3=\frac{8}{2}$

3) Simplify $\frac{8}{2}$ to 4.

$x^3=4$

4) Take the cube root of both sides.

$x=\sqrt[3]{4}$

5) Rewrite 4 as 2².

$x=\sqrt[3]{2^2}$

6) Use this rule: ${({x}^{a})}^{b}={x}^{ab}$ .

$x=2^{\frac{2}{3}}$

Decimal Form: 1.587401

__________________________________________

Check the answer:

$2x^3-8=0$

1) Let $x=2^\frac{2}{3}$ .

$2(2^{\frac{2}{3} })-8=0$

2) Use this rule: $(x^a)^b=x^{ab}$ .

$2\times2^{\frac{2\times3}{3} } -8=0$

3) Simplify 2 * 3 to 6.

$2\times2^{\frac{6}{3} } - 8 =0$

4) Simplify 6/3 to 2.

$2\times2^2-8=0$

5) Use Product Rule: $x^ax^b=x^{a+b}$ .

$2^3-8=0$

6) Simplify 2^3 to 8.

8 - 8 = 0

7) Simplify 8 - 8 to 0.

0 = 0

Thank you,

Eddie

5 0

1 year ago

Hector has three weeks before his first track meet he recorded the amount of time he spent running during week 1 of his training

Fofino [41]

Add them all up so 2 6/12 and 1 6/12 is 4 and then add 1 9/12 to get 5 9/12 or in simple form 5 3/4

6 0

3 years ago

What is-2 |x+7| + 3 =19

RideAnS [48]

-2(x+7)+3=19
-2x-14+3=19
-2x-11=19
-2x=8
x=4

3 0

2 years ago

Read 2 more answers

What is the answer to this

Sphinxa [80]

X= 3/9 is the answer!!

7 0

3 years ago

Write the equation of the line for the following table of values.

Luda [366]

Answer:

We conclude that the equation of the line is:

$y = 5x + 1$

Step-by-step explanation:

The slope-intercept form of the line equation

$y = mx+b$

where

m is the slope

b is the y-intercept

Given the data table

x -3 -5 -7 -9 -11

y -16 -26 -36 -46 -56

From the table taking two points

(-3, -16)

(-5, -26)

Determining the slope between (-3, -16) and (-5, -26)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-3,\:-16\right),\:\left(x_2,\:y_2\right)=\left(-5,\:-26\right)$

$m=\frac{-26-\left(-16\right)}{-5-\left(-3\right)}$

$m=5$

Thus, the slope of the line is: m = 5

substituting m = 5 and (-3, -16) in the slope-intercept form of the line equation to determine the y-intercept b

$y = mx+b$

-16 = 5(-3) + b

-16 = -15 + b

b = -16+15

b = 1

Thus, the y-intercept b = 1

now substituting m = 5 and b = 1 in the slope-intercept form of the line equation

$y = mx+b$

$y = 5x + 1$

Therefore, we conclude that the equation of the line is:

$y = 5x + 1$

5 0

2 years ago