4 years ago

The greater of two consecutive integers is 20 more than twice the smaller. find the integers.

Mathematics

1 answer:

Kipish [7]4 years ago

7 0

Let x represent the smaller. Then x+1 is the greater of the two.

... x+1 = 2x +20

... 0 = x + 19 . . . . . subtract x+1

... x = -19

Your two integers are -19 and -18.

You might be interested in

I need help with this question is it A,B C or D

mixer [17]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the measure for angle f 46 34 122 58

xxMikexx [17]

Answer:

$\angle f = 122\degree$

Step-by-step explanation:

$\angle d = 58\degree$ (vertical angles)

$\angle f+\angle d= 180\degree$

(Interior angles on the same side of transversal)

$\angle f+ 58\degree = 180\degree$

$\angle f = 180\degree-58\degree$

$\huge \orange {\boxed {\angle f = 122\degree}}$

5 0

3 years ago

I've literally asked this question 5 times lol. Can someone please help me?

Tju [1.3M]

I think i know the answer to that question. just wait for a sec.

6 0

3 years ago

Read 2 more answers

Write the equation of the line that passes through the points (4,9) and (9,1). Put

Sonbull [250]

Answer:

y=-8/5x+77/5

Step-by-step explanation:

The equation of line that passes through the points (4, 9) and (9, 1) is y=-8/5x+77/5. Hope it helps!

7 0

3 years ago

Prove that: 5^31–5^29 is divisible by 100.

ANEK [815]

Answer:

See explanation

Step-by-step explanation:

Consider the expression

$5^{31}-5^{29}$

First, factor it:

$5^{31}-5^{29}=5^{29}\cdot(5^2-1)=5^{29}\cdot (25-1)=24\cdot 5^{29}$

Note that

$100=25\cdot 4$

Then

$5^{31}-5^{29}=24\cdot 5^{29}=6\cdot 4\cdot 25\cdot 5^{27}=6\cdot 100\cdot 5^{27}$

This shows that number 100 is a factor of the expression $5^{31}-5^{29}$ and, therefore, this expression is divisible by 100.

5 0

3 years ago