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MAVERICK [17]
3 years ago
7

3x - 8 = 4(x+5) plz plz plz solve it

Mathematics
1 answer:
inn [45]3 years ago
3 0

Answer:

=−28

Step-by-step explanation:

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Prove that for every pair of integers m and n, if n − m is even, then n 2 − m is also even. (You may freely use the fact that th
Romashka [77]

Answer with Step-by-step explanation:

We are given that  n and m are two integers

We have to prove that if n-m is even , then n^2-m is also even.

We know that sum of two odd numbers is even.Sum of an odd number and even number is odd.

Product of an odd number and even number is even.

Case 1.Suppose m and n are both even n=4 , m=2

4-2=2

(4)^2-2=14 =Even

Case 2.Suppose m odd and n odd

n=9,m=5

9-5=4

(9)^2-5=76=Even

Hence, proved.

7 0
3 years ago
Need help 25 points
Zina [86]

Answer:

The answer is 50.27 yards.

Step-by-step explanation:

You divide the diameter in 2, which gives you the radius of 4. Then you must square the radius, or multiply it twice, 4 times 4, to get 16. Then multiply that by pi or 3.14, which is 50.27. Hope this helped and please give brainliest if possible! :)

3 0
3 years ago
Please help WILL MARK BRAINLIEST !!!!
adell [148]

Answer:

100 ft squared

Step-by-step explanation:

5 times 5 for each square

25 times 4

100 ft squared

3 0
2 years ago
Read 2 more answers
If f(x) = 3x + 2, what is f(5)?
emmasim [6.3K]

Answer:

17

Step-by-step explanation:

f(x) = 3x + 2

Let x=5

f(5) = 3*5 + 2

Multiply first

    = 15+2

Then add

    = 17

6 0
2 years ago
Read 2 more answers
A bus company has contracted with a local high school to carry 450 students on a field trip. The company has 18 large buses whic
Galina-37 [17]

Answer:

The answer is below

Step-by-step explanation:

Let x represent the big buses and y represent small buses. The large buses can carry 30 students and the small buses can carry 15 students. The total number of students are 450, this can be represented by the inequality:

30x + 15y ≤ 450

They are only 20 drivers, therefore only 20 buses can be used. It is represented by:

x + y ≤ 20

They  are only 19 small buses and 18 large buses:

x ≤ 18

y ≤ 19

After plotting the graph, the minimum solution to the graph are at:

A (15,0), B(18,0), C(10, 10), D(18, 2).

The cost function is given as:

The total cost of operating one large bus is $225 a day, and the total cost of operating one small bus is $100 per day.

​

F(x, y) = 225x + 100y

At point A:

F(x, y) = 225(15) + 100(0) = $3375

At point B:

F(x, y) = 225(18) + 100(0) = $4050

At point C:

F(x, y) = 225(10) + 100(10) = $3250

At point D:

F(x, y) = 225(18) + 100(2) = $4250

The minimum cost is at point C(10, 10) which is $3250

3 0
3 years ago
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