U(x) = f(x).(gx)
v(x) = f(x) / g(x)
Use chain rule to find u(x) and v(x).
u '(x) = f '(x) g(x) + f(x) g'(x)
v ' (x) = [f '(x) g(x) - f(x) g(x)] / [g(x)]^2
The functions given are piecewise.
You need to use the pieces that include the point x = 1.
You can calculate f '(x) and g '(x) at x =1, as the slopes of the lines that define each function.
And the slopes can be calculated graphycally as run / rise of each graph, around the given point.
f '(x) = slope of f (x); at x = 1, f '(1) = run / rise = 1/1 = 1
g '(x) = slope of g(x); at x = 1, g '(1) = run / rise = 1.5/ 1 = 1.5
You also need f (1) = 1 and g(1) = 2
Then:
u '(1) = f '(1) g(1) + f(1) g'(1) = 1*2 + 1*1.5 = 2 + 1.5 = 3.5
v ' (x) = [f '(1) g(1) - f(1) g(1)] / [g(1)]^2 = [1*2 - 1*1.5] / (2)^2 = [2-1.5]/4 =
= 0.5/4 = 0.125
Answers:
u '(1) = 3.5
v '(1) = 0.125
26 = 3x - 2 - 7x
26 + 2 = -4x
28 / -4 = x
x = -7
Best answer me please!
Answer:
last week = 150 minutes
this week = 162 minutes
changes = 162-150
= 12 minutes
percentage of changes = (12/150) × 100
= 8%
Answer:
1. Can be Paired or Not Paired
2. Paired
3. Not Paired
Step-by-step explanation:
Two sets of observations are paired if each observation in one set has a special correspondence or connection with exactly one observation in the other data set.
1. Can be Paired or Not paired
Reason -
We might look at testing the difference of means using a two sample t-test. However, we may also try running a paired t-test.
But its used in cases where the observations are usually from the same populations at different times or through different sources etc.
Hence can't conclude that it is paired or not paired.
2. Paired
Reason -
Each record is a price of the same item from different stores.
3. Not paired
Reason -
This is again a case of testing the difference of means of two-samples (2 independent samples precisely) that are not paired.
It’s letter d
since m and n are parallel the measure of b will be equivalent to the angle 35 degrees
