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pentagon [3]
3 years ago
12

What is the following product?

Mathematics
2 answers:
ivann1987 [24]3 years ago
6 0

Answer:

30.12-215

Step-by-step explanation:

dem82 [27]3 years ago
6 0
I this the answer is B if I’m right.. hope it helped:)
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What is the answer of 10 to the power of -4<br><br> [tex] 10^-4
malfutka [58]
Remember
x^{-m}= \frac{1}{x^m}

so

10^{-4}= \frac{1}{10^4}= \frac{1}{10000}=0.0001


3 0
3 years ago
Simplify. Your answer should only contain only positive exponents.
Xelga [282]

Answer:

A

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
When the mountain was last measured, its height was 3,570 meters. Now it is 3,927 meters. What is the percent of increase in the
Elina [12.6K]

Answer:

110%

Step-by-step explanation:

3,927/3,570

=1.1

=110%

6 0
3 years ago
3. A company with loud machinery needs to cut its sound intensity to 44% of its original level. By how many decibels would the l
sergeinik [125]

Answer:   <em>3.   The correct option is:  A) 3.57 decibels.</em>

<em>6.   The correct option is:  B) ln(\frac{x^2}{c^5})</em>

Step-by-step explanation:

3.    Sound intensity is cut to 44% of its original level. That means, if the original sound intensity was 100, then now sound intensity will be 44.

So,  I_{0}= 100 and I= 44

Using the formula L= 10log(\frac{I}{I_{0}}), we will get.....

L= 10log(\frac{44}{100})\\ \\ L= 10log(0.44)\\ \\ L= 10(-0.3565...)=-3.565...\approx -3.57

<em>(Rounded to the nearest hundredth)</em>

So, the loudness would be reduced by 3.57 decibels.


6.    Given expression is:    2ln(x) - 5ln(c)

First applying the property m*log(x)= log(x^m) , we will get.....

ln(x^2)-ln(c^5)

Now using the formula, log(a)-log(b)= log(\frac{a}{b}), we will get....

ln(x^2)-ln(c^5) = ln(\frac{x^2}{c^5})

Thus, the answer as a single natural logarithm is   ln(\frac{x^2}{c^5})

8 0
3 years ago
Mindy is purchasing songs from an album on
LekaFEV [45]

Answer:3003

Step-by-step explanation:

14 choose 6 is 3003 because 14!/6!(14-6)!=9*10*11*12*13*14/6!=3003

3 0
3 years ago
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