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3 years ago

Which statements about the trend line in item 3 are true? select all that apply.

Mathematics

1 answer:

natita [175]3 years ago

5 0

Answer:

a and c

Step-by-step explanation:

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Answer:

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2 years ago

you buy dog biscuits at the bulk rate of 2.25/lb. the scale shows .75 lbs fir 25 biscuits. find cost of 40 biscuits

julia-pushkina [17]

1.2 pounds is the weight of 40 biscuits and the cost is $2.70.

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4 years ago

Read 2 more answers

Discuss the validity of the following statement. If the statement is always true, explain why. If not, give a counterexample.

Zigmanuir [339]

Answer:

$P(E \cup F)=P(E)+P(F)$ .

Step-by-step explanation:

Given the statement

If $P(E)+P(F)=P(E \cup F)+P(E \cap F)$ , then E and F are mutually exclusive events.

If two events are mutually exclusive, they have no elements in common. Thus, P(E∩F)=0.

Therefore, the statement is always true as P(E∩F)=0

For mutually exclusive events:

$P(E \cup F)=P(E)+P(F)$ .

3 0

4 years ago

Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon

Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

$h(t)=-16t^2+40t+5$

we know that

When the ball hits the ground, the height is equal to zero

$-16t^2+40t+5=0$

The formula to solve a quadratic equation of the form

$at^{2} +bt+c=0$

is equal to

$t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+40t+5=0$

$a=-16\\b=40\\c=5$

substitute in the formula

$t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}$

$t=\frac{-40\pm\sqrt{1,920}} {-32}$

$t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec$

$t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec$

therefore

The solution is t=2.62 seconds

4 0

3 years ago

Solution of y - x < -3

devlian [24]

Answer:

Step-by-step explanation:

The inequality y - x < -3 should be solved for y, as follows:

Add x to both sides, obtaining:

y < x - 3

Note that this y < x - 3 has the form y = mx + b, which represents a straight line. In this case the straight line would be y = x - 3, meaning that the slope of this line is 1 and the y-intercept is -3.

Because y < x - 3 involves the inequality symbol <, draw a dashed line, not a solid line. The solution set consists of all points on the graph BELOW this dashed line y < x - 3.

8 0

3 years ago

Which statements about the trend line in item 3 are true? select all that apply.​

Which statements about the trend line in item 3 are true? select all that apply.