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vovikov84 [41]
3 years ago
14

When a number is a multiple of another, the GCF of the numbers is the greater of the numbers. Is this always, sometimes, or neve

r true
Mathematics
1 answer:
Mice21 [21]3 years ago
3 0
It depend actually on the number u r given
so technically it is sometimes ☺
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Help me please!!!!!!!!!!
BlackZzzverrR [31]

Answer:

Option (4)

Step-by-step explanation:

In the picture attached,

m∠NLM = m∠LKN = 90°

In two similar triangles ΔLKN and ΔMKL,

By the property of similar triangles,

"Ratio of the corresponding sides of the similar triangles are proportional".

\frac{\text{LK}}{\text{KN}}=\frac{\text{KM}}{\text{LK}}

By substituting the values given,

\frac{h}{3}=\frac{2}{h}

\frac{2}{h}=\frac{h}{3}

Therefore, Option (4) will be the answer.

8 0
3 years ago
If tom makes 50 dollars an hour, how much would he make in 11 hours
Grace [21]

Answer:550

Step-by-step explanation:

5x11 then add a zero from 50 so 550

8 0
3 years ago
Read 2 more answers
HELP ME WITH THIS WORK PLEASEEE
Oksi-84 [34.3K]

Answer:

a is the answer

Step-by-step explanation:

Segment PR is PQ-RE=24-14=10

The probability that a point will be in PR is 10/24 or 0.4166 which rounds up to 0.42

6 0
2 years ago
Write the equation of the line, in point-slope form. Identify (x1, y1) as the point (-2, -1). Use the box provided to submit all
Bas_tet [7]

Answer:

y + 1 = \frac{1}{2} (x + 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - y₁ = m(x - x₁)

where m is the slope and (x₁, y₁ ) a point on the line

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) =(- 2, - 1) and (x₂, y₂ ) = (2, 1) ← 2 points on the line

m = \frac{1+1}{2+2} = \frac{2}{4} = \frac{1}{2}

with point on line (x₁, y₁ ) = (- 2, - 1 ), then

y - (- 1) = \frac{1}{2} (x - (- 2) ), that is

y + 1 = \frac{1}{2}(x + 2) ← equation of line

8 0
3 years ago
Find the measure of each angle indicated
sergey [27]

Step-by-step explanation:

90+115+65=270

360-270=90

Answer:

U=90°

8 0
3 years ago
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