B..............
c>=3 and n<0 and p<=(9-3 c)/n
15 is 16.66666 percent of 90.
Answer: The Median: 78, The First Quartile: 63, and The Third Quartile: 99
Step-by-step explanation: Ok, so let's put the data set from least to greatest....
(63, 63, 76,) (77, 79,) (84, 99, 99)
First Quartile Third Quartile
First, let's find the median, since you made a little mistake...
77 + 79 = 156
156 ÷ 2 = 78
The median is 78!
Now, let's determine the first quartile and the third quartile.
For the the first quartile/third quartile it'll be the middle number, if it's even we'll do the same extra step just like we'll do for the median. In this case it's not even therefore...
First Quartile: 63
Third Quartile: 99
I hope this helps!
Maybe a picture of what the assigment is can help me give you an answer?
Answer:
Step-by-step explanation:
√121 = 11
√900 = √30^2 = 30
∛125 = ∛5^3 = 5
∛729 = ∛9^3 = 9
