Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so
.
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when
.
So




A task time of 177.125s qualify individuals for such training.
63/80 x 100 = 78.8%
You divide normally but multiply by 100 (moving the decimal over two places).
Answer:

Step-by-step explanation:
The given expression is : 
We need to simplify the above expression.
We know that, 
or

So, the simplified form of the given expression is
. Hence, the correct option is (A).
Answer:
239
Step-by-step explanation:
Write the equation. Fill in the given values, and solve for the unknown,
z = k√x
717 = k√9
k = 717/3 = 239
The constant of proportionality is 239.