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3 years ago

What is the absolute value of 2 and 1 therds

Mathematics

1 answer:

sleet_krkn [62]3 years ago

7 0

Answer: 2 and 1 thirds is the answer

Step-by-step explanation:

This is the answer because the absolute value mean how much places the number is away from 0 so 2 1/3 is 2 1/3 away from zero.

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A water sprinkler sends water out in a circular pattern. How many feet away from the sprinkler can it spread water if the area f

myrzilka [38]

Answer:

The sprinkler can spread water 18 feet away.

Step-by-step explanation:

We are given the following in the question:

Area formed by watering pattern = 1,017.36 square feet

We have to find the how far the sprinkler spread the water.

The sprinkler covers a circular area. We need to find the radius of this circular area to find the how far the sprinkler spread the water.

Area of circle =

$A = \pi r^2$

where r is the radius of the circle.

Putting values, we get,

$1017.36 = 3.14 r^2\\\\r^2 = \dfrac{1017.36}{3.14}\\\\r^2 = 324\\r = \sqrt{324} = 18\text{ feet}$

Thus, the sprinkler can spread water 18 feet away.

6 0

3 years ago

Read 2 more answers

the mean height was 69.9 inches with a standard deviation of 3.0 inches. Assume the height data is normally distributed. Zak’s h

sammy [17]

Answer:

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2 years ago

Juan will spend $28 on gifts. So far, he has spent 16. What are the possible additional amounts he will spend?

harina [27]

Answer:

Step-by-step explanation:

because juan is spend 28 on gift and he added a 16 .

7 0

2 years ago

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

7 0

3 years ago

Can someone help me in number 3 please

Sholpan [36]

Area of rectangle is the multiplication between the sides.

The first rectangle:

A = (2x + 5) . (3x - 2)

A = 2x . 3x - 2 . 2x + 5 . 3x - 2 . 5

A = 6x² - 4x + 15x - 10

A = 6x² + 11x - 10

The second rectangle:

A = (5y + 5) . (2y - 3)

A = 5y . 2y - 3 . 5y + 5 . 2y - 3 . 5

A = 10y² - 15y + 10y - 15

A = 10y² - 5y - 15

4 0

3 years ago